@Anivesh90 said:@vijay_chandola None of these.. 5 solns
@sonamaries7 said:none...5
6 solutions will be there
@Anivesh90 said:@rkshtsurana nopes.. but approach?
approach vijay-chandola wali he hai..
yaar B k agar sahi keh rha he toh A ki condition satisfy ho rhi he
A sahi he toh B ki condition satisfu ho rhi he
so D
its nt satisyng for isceles
@vijay_chandola said:if C=90then R=c/2 or c=2*Rand a^2+b^2=c^2=c*2R==> if B is right, then only A will be right.So, option b?
.....but the key gives d? @rkshtsurana
@Anivesh90 said:.....but the key gives d? @rkshtsurana
Yes vice versa is also true! :splat:
a^2+b^2=2Rc implies that C=90.
So, option D hi hona chahiye 😃 :D
@Anivesh90 said:Two mathematicians meet at a bar. After getting drunk A tells B, ” a,b,c are the sides of a triangle, c being the longest. If R is the circumradius of the triangle, a2+ b2= 2Rc”.B replies ” Angle C is 90◦”. Then:a) If A is right then B is rightb) If B is right then A is rightc) at least one is rightd) both of them are righte) none of theseApproach plz.
d?
Circum radius wali nd pythagoras conditions r satisfied only for right angle triangle
Circum radius wali nd pythagoras conditions r satisfied only for right angle triangle
A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms?
(a) 90 (b) 97 (c) 93 (d) 75
@vijay_chandola said:A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms?(a) 90 (b) 97 (c) 93 (d) 75
(d) 75??
@vijay_chandola said:A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms? (a) 90 (b) 97 (c) 93 (d) 75
93 ?
trick kya he
A man invests in Cipro an amount of र60000 in र100 shares sold at a premium of 200%. Cipro offers an annual dividend of 50%. After collecting the dividend at the end of a year, he sells 25% of his shares since their market price had appreciated by 331/3%. After another year, he collects his dividend (again 50%) and sells his remaining shares, the price of which again appreciated by 25%. What is his profit (including the total dividend) from these transactions?
र1,12,500
र52,500
र43,750
र82,500
र1,12,500
र52,500
र43,750
र82,500
@vijay_chandola said:A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms? (a) 90 (b) 97 (c) 93 (d) 75
97 ?
@rkshtsurana said:where is @krum ?
yo!
@vijay_chandola said:A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms? (a) 90 (b) 97 (c) 93 (d) 75
97..?
@vijay_chandola said:A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms? (a) 90 (b) 97 (c) 93 (d) 75
75
@vijay_chandola said:A sequence of non-negative integers is given such that t1 = 150 and tn = t(n - 2) €“ t(n - 1) for n > 2. For what value of t2 would the sequence have the maximum possible number of terms? (a) 90 (b) 97 (c) 93 (d) 75
Am getting 6 non negative terms for 90, 93 & 97.. 
@vijay_chandola said:
t1=150
t2=90/97/93/75
t3=t1-t2=60/53/57/75
t4=t2-t3=30/44/36/0
t5=t3-t4=30/9/21/-
t6=t4-t5=0/35/15/-
t7=t5-t6=30/-/6/-
t8=t6-t7=-/-/9/-
so 93
is majduri se koi chutakara?
t2=90/97/93/75
t3=t1-t2=60/53/57/75
t4=t2-t3=30/44/36/0
t5=t3-t4=30/9/21/-
t6=t4-t5=0/35/15/-
t7=t5-t6=30/-/6/-
t8=t6-t7=-/-/9/-
so 93
is majduri se koi chutakara?