@kinkong said:@audiq7 160 hai..... solve karo..meri gf ne diya hai solve karne ko... izzat ka sawal hai......quants mai numbers ke chapter mai kuch nahi aata jaata re mere ko
160 == 7;
division by 9.
division by 9.
@kinkong said:N=202*20002*200000002*20000000000000002*200...31 zeroes..the sum of the digits in this multiplication is?help karo mamu log
202*20002=40004+4000400=4040404
4040404*200000002*=8080808+808080800000000=8080808080808080
going by the flow, next should be 16 16s and then 32 32s
=>5*32=160
4040404*200000002*=8080808+808080800000000=8080808080808080
going by the flow, next should be 16 16s and then 32 32s
=>5*32=160
thoda detail mai samjhao bhai log.......... usko mail kar dunga copy karke...... concept jara clear karo.........
@catter2011
@sauravd2001 concept samjhao............ kaise kaise solve kiya hai ya thoda detail mai solvve kar do..mail kar dunga usko
@nick_baba said:Two different teams with four students each were training for an internationalmath contest. The students were given an assessment exam andtheir scores were ranked. What is the probability that the four best scorescome from only one of the teams assuming that no two students got the samescore?a) 1/2 b) 1/16c) 1/35 d) 1/288 e) 1/576
c. 1/35
@kinkong this is a short cut tht may work..
sum of digits till a single digit obtained = remainder(N/9) where, N= the number given
going by this we will get 7, but if all the answer options have their sum of digits as 7.
then better follow @krum approach....
sum of digits till a single digit obtained = remainder(N/9) where, N= the number given
going by this we will get 7, but if all the answer options have their sum of digits as 7.
then better follow @krum approach....
sab iim jaane ko marte hai yahan & tcyonline pe iim ke bande civils ko marte hai...pta nahi india ka kya hoga
@kinkong said:sab iim jaane ko marte hai yahan & tcyonline pe iim ke bande civils ko marte hai...pta nahi india ka kya hoga
dost baat IIM ki nai hai..phli cheez..
is thread pe bht se alumni bhi milenge tmhe aur bht se first years bhi jinhone apni engg shuru kari hai..to don think k yahan pe koi IIM jane k liye mar rah hai..it may be a dream for some but its also a HOBBY for many..there are many puys who come and teach us some unimaginable concepts jus for their satisfaction....
@kingkong bhai dekh
202*20002=4040404
4040404*200000002=808080808080808
808080808080808*20000000000000002=16161616161616161616161616161616phir usko 20000..31 zero se mulpitly kar toh answere ayega
3232323232...................yeh 32 ka pair 32 baar ayega toh
sun
3+2=5 ho gaya
aur 32 baar pair banega toh
5*32 karde =160.......bhai maine sarra dimag khali kar liya hai mera is question ke peeche umeed hai bhabhi ko samjh ayega
@kinkong said:@krum apun ko toh kuch samaj nahi aaya...hope tumhari bhabhi ko samaj aa jaye......
@kinkong said:@sauravd2001 concept samjhao............ kaise kaise solve kiya hai ya thoda detail mai solvve kar do..mail kar dunga usko
@kinkong said:sab iim jaane ko marte hai yahan & tcyonline pe iim ke bande civils ko marte hai...pta nahi india ka kya hoga
No spamming is entertained here. 
you can go to shout-box for these things. Not here.
Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
@kingkong bhai ek badiya tarika mila ..............dekh remainder theorem se last ke two terms ayenge 32 aur aise question mein property hoti hai ki terms repeat itself in pair till number of zeros+1 time so u get the answere as 160..................
@nick_baba said:Let A = {a1, a2..ak} be any set of k composite numbers such that1b) 4 c) 5 d) 6 e) 7
3?
@vijay_chandola said:No spamming is entertained here. you can go to shout-box for these things. Not here.Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
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