@vijay_chandola said:No spamming is entertained here. you can go to shout-box for these things. Not here.Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
2
@vijay_chandola said:Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
Ans= 2
Grouping of three - (2+4+1)*33 + 2...AIMCAT sum.
Grouping of three - (2+4+1)*33 + 2...AIMCAT sum.
@vijay_chandola said:No spamming is entertained here. you can go to shout-box for these things. Not here.Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
100mod6=4
2^4mod7=2
200mod6=2
2^2mod7=4
300mod6=0
2^0mod7=1
assuming this cycle repeats as i'm lazy to check beyond 400
=>every pair of 3 numbers is divisible by 7
=>2^10000mod7=2
so 2?
2^4mod7=2
200mod6=2
2^2mod7=4
300mod6=0
2^0mod7=1
assuming this cycle repeats as i'm lazy to check beyond 400
=>every pair of 3 numbers is divisible by 7
=>2^10000mod7=2
so 2?
@vijay_chandola said:No spamming is entertained here. you can go to shout-box for these things. Not here.Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
2^100 mod 7 = 2^99 * 2 = 2 mod 7
2^200 mod 7 = 4 mod 7
2^300 mod 7 = 1 mod 7
2 + 4 + 1 = 7
2^100 + 2^200 + 2^300 + ... + 2^9900 mod 7= 0 mod 7
2^10000 mod 7 = 2 mod 7
So 2
2^200 mod 7 = 4 mod 7
2^300 mod 7 = 1 mod 7
2 + 4 + 1 = 7
2^100 + 2^200 + 2^300 + ... + 2^9900 mod 7= 0 mod 7
2^10000 mod 7 = 2 mod 7
So 2
@vijay_chandola bhai har 3 term ke baad remainder repeat hota hai aur 3 terms ka sum 7 banta hai
tohh
10000/3 =3333 pair hoga
jinka remainder zero hoga
bacha ek term
2^10000/7
jiska remainder 2 hai
@vijay_chandola said:No spamming is entertained here. you can go to shout-box for these things. Not here.Find the remainder when 2^100+2^200+2^300+2^400.......2^10000 is divided by 7.
2 :D
@nick_baba said:Two different teams with four students each were training for an internationalmath contest. The students were given an assessment exam andtheir scores were ranked. What is the probability that the four best scorescome from only one of the teams assuming that no two students got the samescore?a) 1/2 b) 1/16c) 1/35 d) 1/288 e) 1/576
1/2?
@catter2011 bhai ho gaya woh maine 1 ko consideration mein ni liya @kingkong bhai ki izzat bachane mein saara dimag bhai ke question mein lag gaya
In a factory three types of products A, B and C are manufactured. All workers employed in the factory are equally efficient. In one hour, 100 workers can produce 80 A's, 160 B's, 120 C's. In two hours, 75 workers can produce 125 A's, 140 B's and 180 C's. In three hours, 150 workers can produce 150 A's, 'X' B's and 540 C's. What is the value of 'X'?
Q. What is the remainder when a five-digit number PQRSR is divided by 125?
(P, Q, S and R are distinct digits.)
A: A = (PQSR)/4 and A when divided by 25 leaves a remainder 13.
B: R^S = S^R and when a two digit number QR is divided by 10, the remainder is greater than 3.
(P, Q, S and R are distinct digits.)
A: A = (PQSR)/4 and A when divided by 25 leaves a remainder 13.
B: R^S = S^R and when a two digit number QR is divided by 10, the remainder is greater than 3.
Mark (a) if the question cannot be answered even by using both statements together.
Mark (b) if the question can be answered by using both the statements together, but cannot be answered by using either statement alone.
Mark (c) if the question can be answered by using either statement alone.
Mark (d) if the question can be answered by one of the statements alone, but cannot be answered by using the other statement alone.
Mark (b) if the question can be answered by using both the statements together, but cannot be answered by using either statement alone.
Mark (c) if the question can be answered by using either statement alone.
Mark (d) if the question can be answered by one of the statements alone, but cannot be answered by using the other statement alone.
It is given that the quadratic equation X^2 €“ PX + Q = 0 has distinct and real roots, where P and Q are distinct integers. What is the value of (2*P + 3*Q)?
A: Roots of the given equation are consecutive positive integers and (P, Q B: Roots of the given equation are consecutive non-zero integers and (P, Q
Mark (b) if the question can be answered by using both the statements together, but cannot be answered by using either statement alone.
Mark (c) if the question can be answered by using either statement alone.
Mark (d) if the question can be answered by one of the statements alone, but cannot be answered by using the other statement alone.
@krum said:1/2?
@Zedai said:bhai... ans aur approach batao...
nai bhai ..jo OA diya hai wo 1/288 hai..though m not getng it..
@krum mera bhi 1/2 aya tha first time lekin thoda sa gauyr karo to total cases isse kahin zyada niklenge
@bullseyes said:Q. What is the remainder when a five-digit number PQRSR is divided by 125?(P, Q, S and R are distinct digits.)A: A = (PQSR)/4 and A when divided by 25 leaves a remainder 13.B: R^S = S^R and when a two digit number QR is divided by 10, the remainder is greater than 3.Mark (a) if the question cannot be answered even by using both statements together.Mark (b) if the question can be answered by using both the statements together, but cannot be answered by using either statement alone.Mark (c) if the question can be answered by using either statement alone.Mark (d) if the question can be answered by one of the statements alone, but cannot be answered by using the other statement alone.
(c) can be answered alone
@nick_baba said:nai bhai ..jo OA diya hai wo 1/288 hai..though m not getng it..@krum mera bhi 1/2 aya tha first time lekin thoda sa gauyr karo to total cases isse kahin zyada niklenge
@catter2011 said:1/35
@Zedai said:bhai... ans aur approach batao...
m extremely sorry for the trouble guys...OA is 1/35.