At the end of year 2068, Shepard bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p>0 and q>0. If Shepard had nine dozen goats at the end of year 2072, after making the sales for that year, which of the following is true?[1] p = q [2] p [3] p > q [4] p = q/2 is ques ko karne ka koi sahi sa method batao...smthng sort of verbal n logical..n also had there been an option q=p/2..tab kya karte??
the guy will be buying and selling the same no of goats.
but while selling, the no of goats are more in quantity.. so the percentage of goats sold will be less than that of what he bought.
One doubt. Why are we considering the arrangement also over here, why not selection only?
idhar waise select karne ko kuch hain nahi... a,b,c,d in team1 aur e,f,g,h in team-2, dono hi within thoer respected team selected hi hain.. bass unhe arrange karna hain
aur agar hum selection ka case le lenge, i.e 4C4=1 while selecting a,b,c,d from team-1 and similarly from team-2, toh koi difference nahi rahega ..
a,b,c,d a,c,d,b ad,c,b d,a,c,b ... et al mein! infact, sabko ek hi case banega... 4C4=1
isilye arrangement lena padega to consider all these cases..
In a factory three types of products A, B and C are manufactured. All workers employed in the factory are equally efficient. In one hour, 100 workers can produce 80 A's, 160 B's, 120 C's. In two hours, 75 workers can produce 125 A's, 140 B's and 180 C's. In three hours, 150 workers can produce 150 A's, 'X' B's and 540 C's. What is the value of 'X'?
80a+160b+120c=100z 125a+140b+180c=150z 150a+Xb+540c=450z =>a=20b [from first 2 equations]
yep frnz..ans is p>q ..but agar option q=p/2 bhi hota to ??
consider a value 100.. if there is 20% inc. in 100 then to make value back to 100, dec. will be 16.66% which is not less then incremented % but not half of it..
half of the value will be only when the increment will be 100%.
..have a gr8 diwali..