@nick_baba said:m extremely sorry for the trouble guys...OA is 1/35.
2*4!*4!/8! = 1/35
@nick_baba said:m extremely sorry for the trouble guys...OA is 1/35.
bhai, idhar mein apne concepts pe doubt karne laga tha!! 
@bullseyes said:Q. What is the remainder when a five-digit number PQRSR is divided by 125?(P, Q, S and R are distinct digits.)A: A = (PQSR)/4 and A when divided by 25 leaves a remainder 13.B: R^S = S^R and when a two digit number QR is divided by 10, the remainder is greater than 3.Mark (a) if the question cannot be answered even by using both statements together.Mark (b) if the question can be answered by using both the statements together, but cannot be answered by using either statement alone.Mark (c) if the question can be answered by using either statement alone.Mark (d) if the question can be answered by one of the statements alone, but cannot be answered by using the other statement alone.
C?
@Zedai said:bhai, idhar mein apne concepts pe doubt karne laga tha!!
haha..are haan yaar kaam me dhyan hi nai rah tha k galat ans dekhne laga tha...sorry again..tere concepts mast rhenge..cheers..:drink:
@nick_baba said:haha..are haan yaar kaam me dhyan hi nai rah tha k galat ans dekhne laga tha...sorry again..tere concepts mast rhenge..cheers..
lol..koi ni bhai.. 
waise boss saamne baitha hua tha, upar se ans nahi nikal raha tha.. chup chupke qns solve karne ki koshish kar raha tha aise situation mein..
@nick_baba said:@krum bhai wo ai to ak wale ka kuch hua...??
bhai 1/35 to aya tha , zedai ka nai bol kar tumne katta karwa diya
@Zedai said:lol..koi ni bhai.. waise boss saamne baitha hua tha, upar se ans nahi nikal raha tha.. chup chupke qns solve karne ki koshish kar raha tha aise situation mein..
@krum said:bhai 1/35 to aya tha , zedai ka nai bol kar tumne katta karwa diya
aap puys ko pranam..:clap:...chalo lets get back to work ..ek ques aur post karta hu..
@krum said:bhai 1/35 to aya tha , zedai ka nai bol kar tumne katta karwa diya
@Zedai said:lol..koi ni bhai.. waise boss saamne baitha hua tha, upar se ans nahi nikal raha tha.. chup chupke qns solve karne ki koshish kar raha tha aise situation mein..
are app puys ko pranam...
...chalo lets get back to work..ek ques aur post karta hu
...chalo lets get back to work..ek ques aur post karta hu@bullseyes said:It is given that the quadratic equation X^2 €“ PX + Q = 0 has distinct and real roots, where P and Q are distinct integers. What is the value of (2*P + 3*Q)?A: Roots of the given equation are consecutive positive integers and (P, Q B: Roots of the given equation are consecutive non-zero integers and (P, Q Mark (a) if the question cannot be answered even by using both statements together.Mark (b) if the question can be answered by using both the statements together, but cannot be answered by using either statement alone.Mark (c) if the question can be answered by using either statement alone.Mark (d) if the question can be answered by one of the statements alone, but cannot be answered by using the other statement alone.
Is it option (a)?
Since the roots are real and distinct, b^2-4*a*c > 0
Here, p^2 - 4q > 0
From condition a, p and q can be 3,2...4,3...5,4
From condition b, p and q can even assume negative values so there is no way to determine the solutions to the equation
Please correct me if i am wrong
At the end of year 2068, Shepard bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p>0 and q>0. If Shepard had nine dozen goats at the end of year 2072, after making the sales for that year, which of the following is true?
[1] p = q
[1] p = q
[2] p
[3] p > q
[4] p = q/2
is ques ko karne ka koi sahi sa method batao...smthng sort of verbal n logical..n also had there been an option q=p/2..tab kya karte??
@soumitrabengeri said:Is it option (a)?Since the roots are real and distinct, b^2-4*a*c > 0Here, p^2 - 4q > 0From condition a, p and q can be 3,2...4,3...5,4From condition b, p and q can even assume negative values so there is no way to determine the solutions to the equationPlease correct me if i am wrong
wrong.
@Ibanez said:C?
correct
@nick_baba said:At the end of year 2068, Shepard bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p>0 and q>0. If Shepard had nine dozen goats at the end of year 2072, after making the sales for that year, which of the following is true?[1] p = q [2] p [3] p > q [4] p = q/2 n is tarah k ques karne ka koi sahi sa method batao...smthng sort of verbal n logical..
option 3??
@nick_baba said:At the end of year 2068, Shepard bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p>0 and q>0. If Shepard had nine dozen goats at the end of year 2072, after making the sales for that year, which of the following is true?[1] p = q [2] p [3] p > q [4] p = q/2 is ques ko karne ka koi sahi sa method batao...smthng sort of verbal n logical..n also had there been an option q=p/2..tab kya karte??
p>q?
@nick_baba said:At the end of year 2068, Shepard bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p>0 and q>0. If Shepard had nine dozen goats at the end of year 2072, after making the sales for that year, which of the following is true?[1] p = q [2] p [3] p > q [4] p = q/2 is ques ko karne ka koi sahi sa method batao...smthng sort of verbal n logical..n also had there been an option q=p/2..tab kya karte??
option3
@bullseyes said:option 3??
@Zedai said:option 2
@sauravd2001 said:@nick_baba bhai p>q?
yep frnz..ans is p>q ..but agar option q=p/2 bhi hota to ??