Hey I know many of you are not from engineering background..
May be this link will help you to understand graph
www.wolframalpha.com/
Enjoy graphing...
@surajsrivastav said:Hey I know many of you are not from engineering background..May be this link will help you to understand graphwww.wolframalpha.com/Enjoy graphing...
kya baat kar raho ho, yahan most puys Male Engineer ka curse lekar ghoom rahe hain 
@sauravd2001 said:@rkshtsurana bhai option de i got some thing but ptions de i will tell u the answere
options :
0
1
-1
not
@sauravd2001 said:@vikky312 bhai yeh kiya kaise kyunki 34 or 6 rakhi kaise....kiya hua hai pahle ya phir approach bta
yaar cases bana lo:
1: When x--> not possible
2: When 8>x>4 --> 6
3: When x>8 -->34
@sauravd2001 said:@vikky312 bhai kuch kuch aa gaya samjh........kal subah sochunga dhang se baith ke nyways thanx
ha ha...!!
Dekh ek case batata hu, baaki samajh jaayega
case 3: x>8
we have 4,4,4,8,10,20,....x(sumwhere after 8)
Mode=4
Median=8
and mean>8
For AP--> Mean=12
For AP--> Mean=12
So calc x
x=12*7-(4+4+4+8+10+20)
= 34
(x^(1/2))*(x^(1/4))*(x^(1/8))...................to infinity......what will be its value
answere is x tell the approach bhai logon
@sauravd2001 said:(x^(1/2))*(x^(1/4))*(x^(1/8))...................to infinity......what will be its valueanswere is x tell the approach bhai logon
x^ 1/2 + 1/4 + 1/8 ....
infinie gp = 1/2 / 1 - 1/2 = 1
so x^1
@sauravd2001 said:(x^(1/2))*(x^(1/4))*(x^(1/8))...................to infinity......what will be its valueanswere is x tell the approach bhai logon
x^(1/2 + 1/4 + 1/8......)
Infinite GP, S= a/1-r
x,y,z ar ein ap and xyz=4
minimum value of y is ?
answere is 2^(2/3)
approach btao yeh arun sharma mein muskil question ke answere ni diye hote :(
@sauravd2001 said:x,y,z ar ein ap and xyz=4minimum value of y is ?answere is 2^(2/3)approach btao yeh arun sharma mein muskil question ke answere ni diye hote
Teeno numbers ko same le le..AP with cd=0
x*y*z = 4
y^3 =4
y= 4^(1/3)
@sauravd2001 said:x,y,z ar ein ap and xyz=4minimum value of y is ?answere is 2^(2/3)approach btao yeh arun sharma mein muskil question ke answere ni diye hote
always look for AM>GM ,you will get y>= 4^(1/3) hence Answer
@vikky312 are u sure aisa le sakte hain hum? maine pahle yahi kiya tha n i got the answere by this but i doubt ki cd 0 le sakte hain
@sauravd2001 said:@vikky312 are u sure aisa le sakte hain hum? maine pahle yahi kiya tha n i got the answere by this but i doubt ki cd 0 le sakte hain
yaar cd can be anything, positive, negative , zero.