@vikky312 hmm i was just checking this only nyways i got the answere using this earlier ...............thanx buddy
@vikky312 hmm i was just checking this only nyways i got the answere using this earlier ...............thanx buddy
@sauravd2001 said:(x^(1/2))*(x^(1/4))*(x^(1/8))...................to infinity......what will be its valueanswere is x tell the approach bhai logon
1/2+1/4+1/8+1/16.....
=1/2/(1-1/2)=1
=> x^1
two bodies move along a circle in same direction and meet every 49 minute. had they moved at the same speed in oppositre directions,they would have meet every 7 minute.if moving in opposite direction ,the bodies are at a distance of 40m from each other along the arc at time t=0 then at t=24 sec,their distance will be 26 m(bodies donot meet during those 24 seconds).find the speed of faster and slower body both ? help 
@techsurge said:A doctor has to describe 2 new drugs to 200 patients, such that 50 get drug D1 and 50 get drug D2 and 100 get both. The patients are chosen cuh that probability if these patients are not given any of the drug, then they have 80% chances of heart attack. Drug D1 reduces probability of heart attack by 35 % while Drug D2 reduces probability of heart attack by 20 %. The two drugs when taken together work independently. If a patient is selected randomly from 200 patients, what is the probability he is administered both the drugs a) 0.42b) 0.49c) 0.56d) 0.40
yaar this question makes no sense, it will be 100/200=1/2
are u sure the last line is correct so much data is given but question is irrelevant
are u sure the last line is correct so much data is given but question is irrelevant
@techsurge bhai i get .48 😛 because if he is not diagnosed with both drugs then probability is .52 and 1-.52 is .48 toh closest option ke pas agye toh bacha .49 n hamara ans hua yeh..........is kaam mein toh mahir hain hum log
@krum said:yaar this question makes no sense, it will be 100/200=1/2are u sure the last line is correct so much data is given but question is irrelevant
sorry my mistake
the last line will be
If a patient is selected randomly from 200 patients, has a heart attak,what is the probability he is administered both the drugs
@sauravd2001 said:two bodies move along a circle in same direction and meet every 49 minute. had they moved at the same speed in oppositre directions,they would have meet every 7 minute.if moving in opposite direction ,the bodies are at a distance of 40m from each other along the arc at time t=0 then at t=24 sec,their distance will be 26 m(bodies donot meet during those 24 seconds).find the speed of faster and slower body both ? help
(f-s)*49=D
(f+s)*7=D
=>(f-s)/(f+s)=1/7
=>3f=4s
(f+s)*24/60=14
=>(f+s)=35
=>3f+3s=105
=>7s=105
=>s=15,f=20
(f+s)*7=D
=>(f-s)/(f+s)=1/7
=>3f=4s
(f+s)*24/60=14
=>(f+s)=35
=>3f+3s=105
=>7s=105
=>s=15,f=20
@sauravd2001 said:@techsurge bhai i get .48 because if he is not diagnosed with both drugs then probability is .52 and 1-.52 is .48 toh closest option ke pas agye toh bacha .49 n hamara ans hua yeh..........is kaam mein toh mahir hain hum log
question mein ek change tha, edited , attempt again, not 0.48 :P
@krum bhai answere bilkul sahi hai ..........lekin bahut dimag kharab karne wale tarike se nikala hai bhai apne........nywyas yeh dimag kahan se laye ho bhai give me some 😛 i m thinking to ask google people to lent me brain of google for my next cat exam :P
@techsurge said:sorry my mistakethe last line will be If a patient is selected randomly from 200 patients, has a heart attak,what is the probability he is administered both the drugs
in that case
(.8*.65*.8*100)/[(.8*.65*.8*100)+(.8*.65*50)+((.8*.8*50)]
==> wolfram alpha says 0.417671
so .42?
(.8*.65*.8*100)/[(.8*.65*.8*100)+(.8*.65*50)+((.8*.8*50)]
==> wolfram alpha says 0.417671
so .42?
@sauravd2001 said:@krum bhai answere bilkul sahi hai ..........lekin bahut dimag kharab karne wale tarike se nikala hai bhai apne........nywyas yeh dimag kahan se laye ho bhai give me some i m thinking to ask google people to lent me brain of google for my next cat exam
kaun se step mein dimag kharab ho rha hai?
@krum said:in that case(.8*.65*.8*100)/[(.8*.65*.8*100)+(.8*.65*50)+((.8*.8*50)]==> wolfram alpha says 0.417671 so .42?
samjha bhi do 
@techsurge bhai ne sidha formula lagaya ki
p(a)/((p(a)+p(b)+p(c))
aur bhai ne .65 aur .8 isliye liya kyunki usko bechare ko apne heart attack dilva diya
@techsurge bhai lekin yeh bahut calculation intensive ho gaya hai aur muskil bhi toh isko exam mein chor ke aunga main toh agar aisa kuch karke aya toh n agar yahi aya toh iska toh answere dimag mein feed kar liya hai jabhi .42 mark kar aunag :P
@techsurge said:samjha bhi do
take 50 jinhe D1 mila
earlier they had 80% chance of heart attack , i.e 50*.8=40 patients will get heart attack
after drug
=>40*65/100=26 will get heart attack
similarly for 50 who got D2
=>50*80/100*80/100=32
for those who got both, since the drugs work independently, chances will reduce by 65/100*80/100
earlier 100*80/100=80
now 80*65/100*80/100=41.6
so chances of patient getting heart attack after both drugs
=>41.6/(41.6+32+26)
=>0.417670
~.42
earlier they had 80% chance of heart attack , i.e 50*.8=40 patients will get heart attack
after drug
=>40*65/100=26 will get heart attack
similarly for 50 who got D2
=>50*80/100*80/100=32
for those who got both, since the drugs work independently, chances will reduce by 65/100*80/100
earlier 100*80/100=80
now 80*65/100*80/100=41.6
so chances of patient getting heart attack after both drugs
=>41.6/(41.6+32+26)
=>0.417670
~.42
Isosceles triangle ABC has the property that, if D is a point on AC such that BD bisects angle ABC, then triangle ABC and BCD are similar. If BC has length of one unit, then what is the length of AB?
P.S. No OA available
@vijay_chandola said:Isosceles triangle ABC has the property that, if D is a point on AC such that BD bisects angle ABC, then triangle ABC and BCD are similar. If BC has length of one unit, then what is the length of AB?P.S. No OA available
{(1+ root(5))/2}^(1/2)
@vijay_chandola said:Something is wrong Explain.
Wrote Formula for length of median for BD and combined it with similar triangle property. Finally got eqn 2x^4-x^2-1=0 where x is AC. Just realized above ans is wrong
