Official Quant thread for CAT 2013

MBA CAT 2022
1621
@gs4890 said:
yaar wo tab hota jab question is accepting the case of any single persons absence as well. here, it's saying both of them shouldn't be there. it's neither nor either
sahi keh raho bhai, concentration khatam ho chuki hai, bahot jaldi buddha ho gaya hu :splat:
1622

Sorry for the delay


How many scalene triangles can be drawn with distinct sides a,b and c which take integral values less than 8

Answer nahi pata. The options were 12,13, 14, 15 and 16
1623
@Sixty said:
Sorry for the delayHow many scalene triangles can be drawn with distinct sides a,b and c which take integral values less than 8Answer nahi pata. The options were 12,13, 14, 15 and 16
i thnk 12
1624
@Sixty said:
Sorry for the delayHow many scalene triangles can be drawn with distinct sides a,b and c which take integral values less than 8Answer nahi pata. The options were 12,13, 14, 15 and 16
7,6,5; 7,6,4; 7,6,3; 7,6,2; 7,5,4; 7,5,3;
6,5,4; 6,5,3; 6,5,2; 6,4,3
5,4,3; 5,4,2;
4,3,2

13

1625
@krum said:
7,6,5; 7,6,4; 7,6,3; 7,6,2; 7,5,4; 7,5,3;6,5,4; 6,5,3; 6,5,2; 6,4,35,4,3; 5,4,2; 4,3,213
a^ + B^2
123 wala case nhi ayega
1626
@rkshtsurana said:
a^ + B^2 123 wala case nhi ayega
for a triangle sum of two sides should be greater than third side, what you're telling is for acute angle triangle.
1627
@krum : did u count??? 😲
1628

Lcm(x,y).Lcm (y,z) . Lcm(z,x) = xyz gcd(x,y,z)


none of x, y, z is an integer multiple of any other of x, y, z, find the minimum possible value of x + y + z

1629
AIM IIFT
Two friends want to meet at a club. As they are not certain about their schedules, they allow themselves a margin of half an hour. They promise each other that they would be at the club between 5:00 pm and 5:30 pm. The one who arrived first will wait for 5 min or until 5:30 pm. If the person who arrived later arrived within this waiting period, they would meet, otherwise they would be no meeting. What is the probability that they meet?
1/3,2/9,8/27,11/36

1630

@milestogo3 said:
Lcm(x,y).Lcm (y,z) . Lcm(z,x) = xyz gcd(x,y,z)none of x, y, z is an integer multiple of any other of x, y, z, find the minimum possible value of x + y + z
options/?
1631
@rkshtsurana said:
options/?
630
210
250
300
None of these. :D
1632
@pankaj1988 : 1/3 ??
1633
@Brooklyn said:
@pankaj1988 : 1/3 ??


OA:11/36...

1634
@pankaj1988 said:
AIM IIFTTwo friends want to meet at a club. As they are not certain about their schedules, they allow themselves a margin of half an hour. They promise each other that they would be at the club between 5:00 pm and 5:30 pm. The one who arrived first will wait for 5 min or until 5:30 pm. If the person who arrived later arrived within this waiting period, they would meet, otherwise they would be no meeting. What is the probability that they meet?1/3,2/9,8/27,11/36
11/36
1635
@pankaj1988 said:
OA:11/36...
tukka tha !! 😛
@krum said:
11/36
kaise kiya :banghead:
1636
@krum said:
11/36

Bhai thoda prakash daliye....
1637
@rachit_28 said:
Ben and Ann are among 7 contestants from which 4 semifinalists are to be selected. Of the different possible selections, how many contain neither Ben nor Ann?I am getting 25. Please confirm if it's right.
Total contestants = 7
Contestants without Ben and Ann =5
To select 4 = 5c4 Ans
=====
Your approach, which is wrong
Total possible= 7c4 = 35
Unfavourable = 5c2 = 10
Favourable= 7c4-5c2=25 which is wrong


As total possible 7c4 contains all combinations which include both Ben and Ann as well as combinations in which they are alone like _ _ _ _ Ann and not together
For this approach we have to proceed like this
Unfavourable= 5c2+(combinations in which they are alone)
=> 5c2+5c3+5c3 = 10+10+10 =30
FAvourable = 35-30 =5
1638
@Brooklyn said:
tukka tha !! kaise kiya
@pankaj1988 said:
Bhai thoda prakash daliye....
(25*6+5+4+3+2+1)*2/900
=>165*2/900
=>11/45

ye aya mera, to maine 11/36 bol diya

@pankaj1988 exp. hai kya?
1639
@krum
I did the same thing. But technically shouldn't the sum of two sides be greater than or equal to the third. Shouldn't we take into account the equal bit too? That would give 7 more sets
1640
@Sixty said:
@krumI did the same thing. But technically shouldn't the sum of two sides be greater than or equal to the third. Shouldn't we take into account the equal bit too? That would give 7 more sets
not equal, just greater