A Metro train form Mehrauli to Gurgaon has capacity to board 900 people. The fare charged (in `) is defined by the function f =[54-x/32]^2 where 'X' is the number of the people per trip. How many people per trip will make the marginal revenue equal to zero?
A. 1728
B. 576
C. 484
D. 364
OA is B
@surajsrivastav said:A Metro train form Mehrauli to Gurgaon has capacity to board 900 people. The fare charged (in `) is defined by the function f =[54-x/32]^2 where 'X' is the number of the people per trip. How many people per trip will make the marginal revenue equal to zero?A. 1728 B. 576 C. 484 D. 364OA is B
total fare=x*[54-x/32]^2
upon differentiating
x*2*[54-x/32]*-1/32+[54-x/32]^2=0
=>x=576
upon differentiating
x*2*[54-x/32]*-1/32+[54-x/32]^2=0
=>x=576
@surajsrivastav said:@krum Are mjhe pta hai ki ap galat nhi karoge... But sabko Derivation nhi ati na...
differentiate to maine kia, par itne saf suthre form mein isliye likha ki sidhe wolfram pe dal dun :splat:, ab wolf bhaiya galat thode honge :mg:
How many numbers between 200 and 1200 can be formed with digits 0,1,2,3 (no repetition of digits allowed)
I approached like this:
2.3P2 -- 3 digit numbers (without the digit 0) and one 4 digit number (1023) but the OA is 14.
Can you please tell which number am i missing ?
@Sixty said:@krumThis question came in my Deutsche Bank test. It was AIEEE level. Aur questions karoge?
bring it on 
@krum said:(25*6+5+4+3+2+1)*2/900=>165*2/900=>11/45ye aya mera, to maine 11/36 bol diya @pankaj1988 exp. hai kya?
ye kya kiya??? :O
@pankaj1988 said:AIM IIFTTwo friends want to meet at a club. As they are not certain about their schedules, they allow themselves a margin of half an hour. They promise each other that they would be at the club between 5:00 pm and 5:30 pm. The one who arrived first will wait for 5 min or until 5:30 pm. If the person who arrived later arrived within this waiting period, they would meet, otherwise they would be no meeting. What is the probability that they meet?1/3,2/9,8/27,11/36
old question..
draw a graph..
u ll get 22/36*2 = 11/36
draw a graph..
u ll get 22/36*2 = 11/36
@krum said:(25*6+5+4+3+2+1)*2/900=>165*2/900=>11/45ye aya mera, to maine 11/36 bol diya @pankaj1988 exp. hai kya?
Bhai mere paas jo explanation hai usme graphical approach hai...
I dont have any accessory to attach the copy...But I will try my best to make it lucid..Just follow the steps..
Suppose the two friends arrive x minutes and y minutes past 5:00 pm, where 0
Two friends meet when |x-y|
Step1: Draw a square of coordinates O(0,0),B(30,0),E(0,30),D(30,30)
step2: Mark points A(5,0),C(30,25),F(0,5),G(25,30)
step3:sum of areas of triangle will consists of regions(|x-y|>5) when two friends do not meet..so area of triangle ABC+GEF=625
Area of square=900
So the probability when both do not meet=625/900
So the probability when they meet=1-625/900=11/36
@rachit_28 said:How many numbers between 200 and 1200 can be formed with digits 0,1,2,3 (no repetition of digits allowed)I approached like this:2.3P2 -- 3 digit numbers (without the digit 0) and one 4 digit number (1023) but the OA is 14.Can you please tell which number am i missing ?@krum
with 2 _ _= 6 nos
with 3 _ _=6 nos
1023, 1032= 14
@Brooklyn said:ye kya kiya???
@pankaj1988 said:@BrooklynBhai mere paas jo explanation hai usme graphical approach hai...I dont have any accessory to attach the copy...But I will try my best to make it lucid..Just follow the steps..Suppose the two friends arrive x minutes and y minutes past 5:00 pm, where 0Two friends meet when |x-y|Step1: Draw a square of coordinates O(0,0),B(30,0),E(0,30),D(30,30)step2: Mark points A(5,0),C(30,25),F(0,5),G(25,30)step3:sum of areas of triangle will consists of regions(|x-y|>5) when two friends do not meet..so area of triangle ABC+GEF=625Area of square=900So the probability when both do not meet=625/900So the probability when they meet=1-625/900=11/36
are gadbad kar di na
ye hoga - (6+7+8+9+10+10*19+10+9+8+7+6+5)/900=275/900=11/36
ye hoga - (6+7+8+9+10+10*19+10+9+8+7+6+5)/900=275/900=11/36
@rachit_28 said:How many numbers between 200 and 1200 can be formed with digits 0,1,2,3 (no repetition of digits allowed)I approached like this:2.3P2 -- 3 digit numbers (without the digit 0) and one 4 digit number (1023) but the OA is 14.Can you please tell which number am i missing ?@krum
2/3 _ _ - 2*6=12
1023
1032
14
1023
1032
14
@surajsrivastav said:A Metro train form Mehrauli to Gurgaon has capacity to board 900 people. The fare charged (in `) is defined by the function f =[54-x/32]^2 where 'X' is the number of the people per trip. How many people per trip will make the marginal revenue equal to zero?A. 1728 B. 576 C. 484 D. 364OA is B
Total fair is F(x)=x*f(x)
Marginal Revenue is given by: F'(x)=0
x*2*(54-x/32)(-1/32)+(54-x/32)^2=0
x=576
There are 8 orators A,B,C,D,E,F,G,H. in how many ways can the arrangements be made so that A always comes before B and B before C?
iska 8!/3! hoga naa ?
@rachit_28 said:There are 8 orators A,B,C,D,E,F,G,H. in how many ways can the arrangements be made so that A always comes before B and B before C?iska 8!/3! hoga naa ?@krum@maddy2807
sahi hai 8!/3!
@rachit_28 said:There are 8 orators A,B,C,D,E,F,G,H. in how many ways can the arrangements be made so that A always comes before B and B before C?iska 8!/3! hoga naa ?@krum@maddy2807
sahi 
@rachit_28 said:There are 8 orators A,B,C,D,E,F,G,H. in how many ways can the arrangements be made so that A always comes before B and B before C?iska 8!/3! hoga naa ?@krum@maddy2807
In how many ways we can select four cards of different suits & different denominations from a deck of 52 cards??
Confusion is between : 52 X 36 X 22 X 10
and 13 X 12 X 11 X 10
Confusion is between : 52 X 36 X 22 X 10
and 13 X 12 X 11 X 10
@maddy2807 said:In how many ways we can select four cards of different suits & different denominations from a deck of 52 cards??Confusion is between : 52 X 36 X 22 X 10and 13 X 12 X 11 X 10@krum
4c1*13c1*3c1*12c1*2c1*11c1*1c1*10c1