Find the least number of ways of choosing three different numbers from 1 to 10 so that all choices have the same sum.
ABC is an equilateral triangle whose sides are of length 1cm. If we select 5 points inside the triangle , is it true that atleast two of these points are such that the distance between them is less than 1/2 cm. how or why??
@kingsleyx said:Find the least number of ways of choosing three different numbers from 1 to 10 so that all choices have the same sum.
42??? wats the oa
@kingsleyx kk its as good as choosing three nos or combination of three nos..
eg
1,2,3 r the three nos which will give the same sum & can be chosen randomly in 6 ways
imo..sol hai kya
@kingsleyx said:ABC is an equilateral triangle whose sides are of length 1cm. If we select 5 points inside the triangle , is it true that atleast two of these points are such that the distance between them is less than 1/2 cm. how or why??
yes its true.
Can't think of a proof but you should be able to visualize it
Can't think of a proof but you should be able to visualize it
@krum said:yes its true. Can't think of a proof but you should be able to visualize it
connect the midpoints and place the points.
@milestogo3 said:a1.a3 = a2 ^2 +1a1.a3 = 26a3 =13now you can calculate a4 =34a6 = 233and therefore a(7) comes to be 610some other approach?
bhai did not understand a1.a3 = 26
after that how did you decide a3 =13??
@soumitrabengeri : bhai ye bookmark kaise karna?? you have book marked the link or the post by angad sir?? there was a feature to make a particular post favorites or something like that. but unable to find in this new version 😞
@Fuhgetaboutit said:ABC is a triangle. AB = 3 units AC = 5 units BC = Square root of 10 unitsAD is the angle bisector of angle A which intersects BC at D.What is the ratio of BD: DC?
3:5
@Fuhgetaboutit said:How?
angle bisector theorem..angle bisector divides the opposite sides in the same ratio of the sides containing the angle
For CWG taxis are brought into service.Half way going during the opening Ceremony ,10 taxis broke down.Hence each taxi had to carry one more person to equalize the load. At the time of returning from opening Ceremony 15 more taxis were not working,hence each taxi has to carry 3 more people than what they started out in the morning.. Find the number of people who attended CWG ceremony?
XM = (X-10 ) (M+1) = (X-25) (M+3)
solving first 2 and last 2
then we will get X = 100 and M = 9
so total = 900
@Fuhgetaboutit said:ABC is a triangle. AB = 3 units AC = 5 units BC = Square root of 10 unitsAD is the angle bisector of angle A which intersects BC at D.What is the ratio of BD: DC?
Let BD=X so DC=SQRT10 - X
Angle bisector theorem:
AC/AB=CD/DB
5/3=sqrt(10)-x / x
x=BD=3sqrt10/8
DC=5sqrt10/8
BD:DC=3:5
@chandrakant.k said:bhai did not understand a1.a3 = 26after that how did you decide a3 =13??@soumitrabengeri : bhai ye bookmark kaise karna?? you have book marked the link or the post by angad sir?? there was a feature to make a particular post favorites or something like that. but unable to find in this new version
i have bookmarked the link to that particular page..not that particular post..
@gyrodceite said:XM = (X-10 ) (M+1) = (X-25) (M+3)solving first 2 and last 2then we will get X = 100 and M = 9so total = 900
Even i am getting the same equation and answer..isn't it matching with the OA??
P.S. Your signature..
..1st jan 2013..cant wait
..1st jan 2013..cant wait@soumitrabengeri said:Even i am getting the same equation and answer..isn't it matching with the OA??P.S. Your signature....1st jan 2013..cant wait
I just had a question No OA..:)
dono ka matching to thik hoga.
Yes 1st january...\m/
dono ka matching to thik hoga.
Yes 1st january...\m/
A product can be produced either on machine A or B. It takes 3 hrs to set up A and then 15 min to produce each unit. Machine B takes 4 hrs to set up and then it produce each unit in only 12 min. A total of 60 units have to be produced .If both the machine can be used and the job has to be done in minimum possible time, how many units should be produced by A?,
29,32,28,31..
P.S. plz post soln
@pankaj1988 said:A product can be produced either on machine A or B. It takes 3 hrs to set up A and then 15 min to produce each unit. Machine B takes 4 hrs to set up and then it produce each unit in only 12 min. A total of 60 units have to be produced .If both the machine can be used and the job has to be done in minimum possible time, how many units should be produced by A?,29,32,28,31..P.S. plz post soln
Is it 29?