Official Quant thread for CAT 2013

@grkkrg said:
Sarees made from cloth type A.Cloth type B made from cotton.Cotton is made from yarn.I. Correct.If A and B intersection is not a null set then can be true.II. IncorrectIf A and B intersection is a null set then can be false.III. Incorrect"Some" cloth is made from some yarn.


bhai venn diag batana aise nahi pata chal ra hai...

@grkkrg said:
Sarees made from cloth type A.Cloth type B made from cotton.Cotton is made from yarn.I. Correct.If A and B intersection is not a null set then can be true.II. IncorrectIf A and B intersection is a null set then can be false.III. Incorrect"Some" cloth is made from some yarn.
Agree about 3 being incorrect..should be some cloth is made from some yarn..but then yarn and saree is not connected..so 1 can be true only for a specific condition? And since it is an affirmative statement..there is no need to draw an alternate diagram
@antodaya said:
Some sarees are made from cloth. Some cloth is made from cotton. Cotton is made from yarn.I. Yarn may be used to make some sarees.II. Cotton is used to make some sarees. III. Cloth is made from some yarn.ps:approach bata dena yar..
If the question says find the conclusion which can be derived using all the three statements

=> I is the conclusion

If the question says find the conclusion which can be derived using any two of the three statements

=> I & III are the conclusions

@antodaya said:
kaise kia yar batana..mera venn diag to aise aa raha hai...
Your venn seems correct to me
@soumitrabengeri said:
Agree about 3 being incorrect..should be some cloth is made from some yarn..but then yarn and saree is not connected..so 1 can be true only for a specific condition? And since it is an affirmative statement..there is no need to draw an alternate diagram
1 can be true only for a specific condition.
The statement has a "maybe".



@antodaya said:
bhai venn diag batana aise nahi pata chal ra hai...
bhai aapke venn diagram me yarn aur saree ke sets intersect ho sakte hain
There is a "maybe" given.
@antodaya said:
Some sarees are made from cloth. Some cloth is made from cotton. Cotton is made from yarn.I. Yarn may be used to make some sarees.II. Cotton is used to make some sarees. III. Cloth is made from some yarn.ps:approach bata dena yar..
I hoga kya ?

may or may not be for II and III
@grkkrg said:
1 can be true only for a specific condition. The statement has a "maybe".bhai aapke venn diagram me yarn aur saree ke sets intersect ho sakte hainThere is a "maybe" given.
Agreed..so should we consider that case? Normally for affirmative statements we do not draw an alternate diagram..I am using a TIME method..so maybe wrong..but if it is a negative statement, that is when we draw an AD, right?
@grkkrg said:
1 can be true only for a specific condition. The statement has a "maybe".bhai aapke venn diagram me yarn aur saree ke sets intersect ho sakte hainThere is a "maybe" given.
haan got it..."maybe" hai...

Maine aise banaye venn, 2nd sabko follow kar rha. DO tell where I'm wrong. Confused :/

A coin of diameter d is thrown randmly on a floor tiled with squares of side l. Two players bet that the coin will land on exactly one, respectively, more than one, square. What relation should l and d satisfy for the game to be fair?

@jain4444 - welcome!!!!
@Torque024 said:
Maine aise banaye venn, 2nd sabko follow kar rha. DO tell where I'm wrong. Confused :/
you have to consider worst case scenario here

@rkshtsurana pranam bhai ____/\____
@antodaya bhai 1 ayega kya?
@pankaj1988 said:
Let BD=X so DC=SQRT10 - XAngle bisector theorem:AC/AB=CD/DB5/3=sqrt(10)-x / xx=BD=3sqrt10/8DC=5sqrt10/8BDC=3:5
dis was my cat question 6th nov 10:00 a.m.
@Torque024 all cases need to be considered.

@rkshtsurana said:
A coin of diameter d is thrown randmly on a floor tiled with squares of side l. Two players bet that the coin will land on exactly one, respectively, more than one, square. What relation should l and d satisfy for the game to be fair? @jain4444 - welcome!!!!
First player will win with 100% chance when square exactly circumscribes the coin..
that is if side of square is d
but side of tile is l
50 -50 k liye l-d ka square ka area half ho puri tile(side l ) ke
(l-d)^2 = l^2 /2
l = (2 + rt2)d
18^2000 + 12^2000 - 5^2000 - 1 is divisible by

323,221,299,237
@rkshtsurana bhai answere bta deta hun approach btaiyo 221
@sauravd2001 said:
18^2000 + 12^2000 - 5^2000 - 1 is divisible by323,221,299,237
17 x 19 = 323 ?
@rkshtsurana bhai aa gaya samjh
dekh( a^n-b^n) toh property hoti hai a+b or a-b se divide hota hai
dekh dodno mein se 17 aur 13 common ayega toh
13 aur 17 =221...........................ab confidence aya thoda do din se katta hoye ja raha hai bahut question mein

last five terms of 41^24000001