what will be the 28383rd term of series:123456789101112.........
a)3,b)4c)5d)6
2)
The LCM of these 3 is 180 then 364 is the answer
quote=Bwhoopee;1008691]Question no. 1. Find the remainder when 73 * 75 * 78 * 57 * 197 is divided by 34.
a) 32 b)30 c)15 d) 28
Question no. 2 Find the least number that when divided by 16,18 and 20 leaves a remainder 4 in each case, but is completely divisible by 7.
a) 364 b)2254 c)2964 d)3234 e)2884
question no. 3 If 2
options are 6, 7, 8 and 4
#newbie
As we have 10 in 70 and in 35 or 55 has 5 and you have 2 in 56,44...
This will make the factors of 100 whic make the end digits 00
or
in clinical approach
you may take the reminders of 100 from each and make the solution
-33*-44*-29*-45*-30*35*44
Taking factors and finding te reminder by grouping them to be near to 100
can anyone lemme knw whts the shortest way to find last two digits of an expression like
67*56*71*55*70*35*44
This is answered earlier.
Anser is and the method is the same as the reply
what will be the 28383rd term of series:123456789101112.........
a)3,b)4c)5d)6
9*1+90*2+900*3=2889
28383-2889=25494
when divided by 4 , 25494 gives , quotient 6374 and remainder
so the 28383 term of the series will be 2nd digit of the 999+6375=7374
so the term is 3
Yaar Imlex..can u be more clear..i coudnt get u????
Sure..
for 1-9 only one digit
10-99 ,90 terms 2 digits each 90*2
100-999.900 terms with 3 digit 900*3
Need more explanation?
ashwinrulz SaysYaar Imlex..can u be more clear..i coudnt get u????
so we need to find 2^53%10
2^5%10 is 2
((2^5)^5)^2*2^3
2^5%10=2
ashwinrulz SaysYaar Imlex..can u be more clear..i coudnt get u????
lod-2-numbers
91)What is the rightmost digit preceeding the zeros in the value 20^53
=-1^(66*67*133)/6
=-1^ odd number so reminder is 5-1 or 4
lod-2-numbers
75)Reamainder when 22334^(1^2+2^2+......+66^2) is divided by 5.
Sure..
for 1-9 only one digit
10-99 ,90 terms 2 digits each 90*2
100-999.900 terms with 3 digit 900*3
Need more explanation?
yea got it dude..thx
NUMBER SYSTEM lod 3
53. what is the remainder when 128^1000 is divided by 153
a)103 b)145 c)118 d)52
54. find the remainder when 50^51^52 is divided by 11.
a)6 b)4 c)7 d)3
Please explain the answers guys....
thanks in advance
cheers
vidhyasagar
EN for 11=10
51^52=(50+1)^52 .. therefore gives remainder 1 on dividing by 10
N=50^51^52=50^(10k+1)
so remainder is 50 as 50^10k gives remainder 1
so final remainder is 6
option a
Please can you elaborate. I didn't get you. And what is EN ?
NUMBER SYSTEM lod 3
53. what is the remainder when 128^1000 is divided by 153
a)103 b)145 c)118 d)52
54. find the remainder when 50^51^52 is divided by 11.
a)6 b)4 c)7 d)3
Please explain the answers guys....
thanks in advance
cheers
vidhyasagar
53 a) I have another method.
Now you must know that
say if rem of N/x = R
and a and b are factors of x. And rem of N/a = r1 and rem of N/b = r2
then rem of R/a is also r1 and rem of R/b is also r2.
Now the sum.
128^1000 = 2^7000 = N
and 153 = 9 * 17
Now N/9 = (2^3)^2333 * 2/9
rem = -2 = 7
rem of N/17 = (2^4)^1750/17 = 1
Now search the options. Find such a number R such that rem of R/9 = 7 and R/17 = 1
only 52 matches the criteria
50^51^52%11=========>-5^51^52 5^2=25%11=3, 5^3=125%11=4
4*3=12%11=1
so
-5^51%11====>-5
-5^52%11====25%11===>3
NUMBER SYSTEM lod 3
54. find the remainder when 50^51^52 is divided by 11.
a)6 b)4 c)7 d)3
Please explain the answers guys....
thanks in advance
cheers
vidhyasagar
Nos with 1 digit = 9
Nos with two digit = 99 - 9 = 90
Nos with three digit = 999 - 99 = 900
So total digits upto 999 = 2700 + 180 + 9 = 2889
Remaining = 28383 - 2889 = 25494
So the numbers with four digit until the 28383rd term = 25494/4 = 6373 Remainder 2
So 999 + 6373 = 7372
So 2nd term of nest number 7373 = 3
Answer ---- 3
Hope this is correct
-------------------------------
In the solution above, why did you add 999 with 6373 .
can anyone plz let me know weather ans of lod1 and lod2 r given in arun sharma???act i have not bought d buk n im still confused bw arun sharma n rs agarwal n have read in a simliar type of thread dat ans r not given in arun sharma......
sismis Sayscan anyone plz let me know weather ans of lod1 and lod2 r given in arun sharma???act i have not bought d buk n im still confused bw arun sharma n rs agarwal n have read in a simliar type of thread dat ans r not given in arun sharma......
hey...buddy...der wont be answers for lod1 ....but u have hints for lod2 and lod3...dat 2 not 4 all questionz..only 4 few..dat to vry precise....i mean suppose u r not able to sole sme q say 23 in lod2....der is possibility of not findin hint for dat particular question....
but not to worry u have this thread through which u could get ya doubts cleared,,,,,
i dono ant rs agarwal...but ya arun sharma is gud..with quality questionz...and stufz....but if u r a beginner i wont recoment u dat buk...its beter u start of with coachin materials(Time is gud)..den swithch over arun sharma./....
newayz...keep rockin.....
sismis Sayscan anyone plz let me know weather ans of lod1 and lod2 r given in arun sharma???act i have not bought d buk n im still confused bw arun sharma n rs agarwal n have read in a simliar type of thread dat ans r not given in arun sharma......
Buy "Quantum CAT" by Sarvesh Kumar Verma ; "Arihant Publications".
This book is far better than Arun Sharma and Abhijeet Guha.
When you are through with Sarvesh Kumar..........feel free to grind through Arun Sharma.
All right.. just read the "preface" of all three books with some book shop.
The last thing => every question is solved in Verma !
good luck
Hello there
I need help on doing the 6th question on page 42. LODII. Number Systems
Thanks
Scribbles
Hello there
I need help on doing the 6th question on page 42. LODII. Number Systems
Thanks
Scribbles
The question u have asked for is
(sqrt of x+2(sqrt x+2 (sqrt x+2 (sqrt 3x))))=x
This is easy..for these kind of questions just go by the options..
the option u get after taking the value of x=3 will give u the answer as 3..
try substituting..
(sqrt of x+2(sqrt x+2 (sqrt x+2 (sqrt 3(3)))))=x
(sqrt of x+2(sqrt x+2 (sqrt x+2 (sqrt 9))))=x
(sqrt of x+2(sqrt x+2 (sqrt x+2 (3))))=x
(sqrt of x+2(sqrt x+2 (sqrt 3+6)))=x
(sqrt of x+2(sqrt x+2 (sqrt 9)))=x
(sqrt of x+2(sqrt x+2 (3)))=x
(sqrt of x+2(sqrt 3+6))=x
(sqrt of x+2(sqrt 9))=x
(sqrt of x+2(3))=x
(sqrt of 3+6)=x
(sqrt of 9)=3
Hope its clear now :)!
hi puys...
i hav started quants in arun sharma now:confused:
i kno basics(wich i learnt from times material) but havent tried those exercises
do i hav the time to complete the book arun sharma within these 7 months?:confused: