Please help me with this question.. The answer is given but want to know the solution
TIME SPEED DISTANCE
LOD 1
Ques. no. 6
Shyam's house, his office and his gym are equidistant from each other. The distance between any 2 of them is 4 km. Shyam starts walking from his gym in a direction parallel to the road connecting hos office and his house and stops when he reaches a point directly east of his office. He then reverses his direction and walks till he reaches a point directly south of his office. The total distance walked by Shyam is
(a) 6 Km
(b) 9 Km
(c) 16 Km
(d) 12 Km
(e) 8 Km
hey...buddy...der wont be answers for lod1 ....but u have hints for lod2 and lod3...dat 2 not 4 all questionz..only 4 few..dat to vry precise....i mean suppose u r not able to sole sme q say 23 in lod2....der is possibility of not findin hint for dat particular question....
but not to worry u have this thread through which u could get ya doubts cleared,,,,,
i dono ant rs agarwal...but ya arun sharma is gud..with quality questionz...and stufz....but if u r a beginner i wont recoment u dat buk...its beter u start of with coachin materials(Time is gud)..den swithch over arun sharma./....
newayz...keep rockin.....
Hi.. I bought the second edition of the boook called 'Quantitative Aptitude for CAT' by Arun Sharma yesterday.. Answer key is given to all the problems (LOD 1, 2 and 3) and hints & solutions are given for some specific problems only.. Hope that helps..
i hav solved few chapters in rs aggarwal... all r solved problems
problems r good but not that standard...and very few shortcuts
Please help me with this question.. The answer is given but want to know the solution
TIME SPEED DISTANCE
LOD 1
Ques. no. 6
Shyam's house, his office and his gym are equidistant from each other. The distance between any 2 of them is 4 km. Shyam starts walking from his gym in a direction parallel to the road connecting hos office and his house and stops when he reaches a point directly east of his office. He then reverses his direction and walks till he reaches a point directly south of his office. The total distance walked by Shyam is
(a) 6 Km
(b) 9 Km
(c) 16 Km
(d) 12 Km
(e) 8 Km
he walks 12 kms..
pallaviagrawal Sayshe walks 12 kms..
how did u get it??wats the method u applied plz explain
pallaviagrawal Sayshe walks 12 kms..
ya the answer is given as 12 in the book.. pls throw some light on the solution..
guneet_01 Saysya the answer is given as 12 in the book.. pls throw some light on the solution..
office(O) ,gym(G) and house(H) are equidistant..so we can assume them to be at three corners of an equilateral triangle with vertices O ,G and H.the man starts walking from G in a direction parallel to OH and reaches a point P(OGPH forming a quadilateral ).now using simple geometry we know that this point will be exactly east of O only if the quad. OGPH is a parallelogram with equal sides OG,GP,PH and OH.so he has walked 4 kms..now he goes back the same path and reaches a point D xactly south of O,therefore OPD is a right angled triangle right angeled at O..now ,triangle OPD is equilateral since angle DOG =angle DGO=60 degrees.therefore..GD=OG=4kms.
total distance travelled=GP+GP+DG=4+4+4=12kms.
office(O) ,gym(G) and house(H) are equidistant..so we can assume them to be at three corners of an equilateral triangle with vertices O ,G and H.the man starts walking from G in a direction parallel to OH and reaches a point P(OGPH forming a quadilateral ).now using simple geometry we know that this point will be exactly east of O only if the quad. OGPH is a parallelogram with equal sides OG,GP,PH and OH.so he has walked 4 kms..now he goes back the same path and reaches a point D xactly south of O,therefore OPD is a right angled triangle right angeled at O..now ,triangle OPD is equilateral since angle DOG =angle DGO=60 degrees.therefore..GD=OG=4kms.
total distance travelled=GP+GP+DG=4+4+4=12kms.
hey thanks! pls let me know is the point D lying on the line GH or below/above it?
And also, why is angle DOG equal to angle DGO equal to 60 degrees?
hey thanks! pls let me know is the point D lying on the line GH or below/above it?
depends on how u have drawn the figure :|
2nd part,
angle OGP=120 since the sides are equal..so angle OGD=60.now,angle GOP=30,and angle DOP=90,so angle GOD=90-30=60.
i kno the following question is basic's
its in arun sharma number systems try yourself
i am bit confused abt the solution....
plz explain me the following question
what is the remainder
1)when 43^197 is divided by 7??
2)when 67^99 is divided by 7?
i kno the following question is basic's
its in arun sharma number systems try yourself
i am bit confused abt the solution....
plz explain me the following question
what is the remainder
1)when 43^197 is divided by 7??
2)when 67^99 is divided by 7?
I think both the answers are 1..... First one I'm sure of it, maybe even the 2nd one.... If they're correct, I'll let you know the solution
i kno the following question is basic's
its in arun sharma number systems try yourself
i am bit confused abt the solution....
plz explain me the following question
what is the remainder
1)when 43^197 is divided by 7??
2)when 67^99 is divided by 7?
The answer to both the question is 1, here goes the solution
1) 43/7 gives a rem of 1, so the prob reduces to finding the rem of 1^197/7, which is 1
2) I am doing this using euler's theorem, 67^6/7 will give a rem of 1, hence 67^96/7 will give a rem of 1, we are left with 67^3/7 which is equivalent to 4^3/7 which give a rem of 1, hence the rem is 1.
For more on rem problems please see the number system thread for cat 08
This is question no. 14 in LOD 2 of Time Speed Distance chapter in Arun Sharma's Quant book:
Two indian tourists in the US cycled towards each other, one from point A and the other from point B. The first tourist left point A 6 hrs later than the second left point B, and it turned that he travelled 12 km less than the second tourist. After their meeting, they kept cycling with the same speed, and the first tourist arrived at B 8 hours later and the second arrived at A 9 hours later. Find the speed of the faster tourist.
(a) 4 km/hr
(b) 6 km/hr
(c) 9 km/hr
(d) 2 km/hr
(e) 5 km/hr
The answer to both the question is 1, here goes the solution
1) 43/7 gives a rem of 1, so the prob reduces to finding the rem of 1^197/7, which is 1
2) I am doing this using euler's theorem, 67^6/7 will give a rem of 1, hence 67^96/7 will give a rem of 1, we are left with 67^3/7 which is equivalent to 4^3/7 which give a rem of 1, hence the rem is 1.
For more on rem problems please see the number system thread for cat 08
first of all thanks asghan and avinav
the question 43^197 is in page 30 arun sharma ...i too thot 1 as the answer but the solution in the book is given as 2!!!!!!!!!!!!!!
many r givn wrong i assumeand 2nd question is rite
thanks once again
This is question no. 14 in LOD 2 of Time Speed Distance chapter in Arun Sharma's Quant book:
Two indian tourists in the US cycled towards each other, one from point A and the other from point B. The first tourist left point A 6 hrs later than the second left point B, and it turned that he travelled 12 km less than the second tourist. After their meeting, they kept cycling with the same speed, and the first tourist arrived at B 8 hours later and the second arrived at A 9 hours later. Find the speed of the faster tourist.
(a) 4 km/hr
(b) 6 km/hr
(c) 9 km/hr
(d) 2 km/hr
(e) 5 km/hr
hey bro
i solvd the problem only to get the speed of the faster tourist 6km/hrand tat of the other 4km/hr
but the solution given in the book is converse:nervous:
lets wait fa answers 4m experienced puy's:robot:
hey broi solvd the problem only to get the speed of the faster tourist 6km/hr
and tat of the other 4km/hr
but the solution given in the book is converse:nervous:
lets wait fa answers 4m experienced puy's:robot:
Speed of the faster tourist is indeed 6 Km/h. Many keys given in that book is wrong.
mejogi SaysSpeed of the faster tourist is indeed 6 Km/h. Many keys given in that book is wrong.
ya:unhappy:it isnt one or two many are wrong!!!sometimes 4-5 in a row putting us in a state of confusion!!i am new to this book:-?
thankz mejogi for clearing ma doubt:)
in a town consisting of p persons x% can read and write . of the males alone y%.and of the females alone z% can read and write.find the number of males in the village in terms of p,x,yand z if z
p(y-x)/(x-z)
p(x-z)/(y-z)
plz give d answer
there are three galleries in a coal mine.On the first day ,two galleries are operative and after some time ,the third gallery is made operative.With this,the output of the mine became half as large again . what is the capacity of the second gallery as a percentage of the first;if it is given that a four-month output of the first and the third galleries was the same as the annual output of the second gallery ?
70 %
64 %
60 %
None Of These
in a town consisting of p persons x% can read and write . of the males alone y%.and of the females alone z% can read and write.find the number of males in the village in terms of p,x,yand z if zp(x-z)/(y+x-2z)
p(y-x)/(x-z)
p(x-z)/(y-z)
plz give d answer
I think the answer of this one is option D