@amitranjan2311 said:@anilapex16Can you please share your approach,bro?It will be more helpful if you elaborate it.Thanks.
In such questions where the remainder comes out to be the same.... find the HCF of the difference between the given numbers..and that will be the required answer.... say the numbers be A+r, B+r, C+r so on calculating the difference u will be able to eliminate the remainder part that is common to all the three numbers... the above question is reduced to find the HCF of 32, 48, 80. now solve and u will get 16 as the answer..
q) Each of the two cars is sold at the same price. A profit of 10% is made on the first and a loss of 7% is made on the second.What is the combined loss or gain? Thanks in Advance (Ans is 160/203%)
q) Each of the two cars is sold at the same price. A profit of 10% is made on the first and a loss of 7% is made on the second.What is the combined loss or gain? Thanks in Advance(Ans is 160/203%)
First we have to consider the number to standard form. Standard form is when a number is expressed as product of powers of prime numbers.1080= 2*2*2*5*3*3*3 = 2^3*3^3*5^1Factors that are perfect squares are 1,2^2,3^2,2^2*3^2The number of factors of 1080 are = 4*4*2 = 32Excluding the perfect squares, the number of factors are 32-4=28.Hope it helps.
Thank you very much.
I had got the answer with a slightly different method.
1080 = 2^3*3^3*5^1 Total no.of factors = 4*4*2 = 32
For getting the square factors, we can only include even powers + zero powers
So, 1080 = 2^3*3^3*5^1 = (2^0+2^1+2^2+2^3)(3^0+3^1+3^2+3^3)(5^0+5^1)
I was just wondering if their is a direct way for solving this, in which we don't need subtraction at the end i.e. if we can directly calculate no.of non square factors as we directly calculated no.of square factors.
Thank you very much.I had got the answer with a slightly different method.1080 = 2^3*3^3*5^1Total no.of factors = 4*4*2 = 32For getting the square factors, we can only include even powers + zero powersSo, 1080 = 2^3*3^3*5^1= (2^0+2^1+2^2+2^3)(3^0+3^1+3^2+3^3)(5^0+5^1)becomes= (2^0+2^2)(3^0+3^2)(5^0)No.of square factors = 2*2*1 = 4No.of non square factors = 32 - 4 = 28I was just wondering if their is a direct way for solving this, in which we don't need subtraction at the end i.e. if we can directly calculate no.of non square factors as we directly calculated no.of square factors.
The using of zero powers and even powers is good.
And about the direct way, i dont think there is one.
Q11 . A no. is mistakenly divided by 5 instead of being multiplied by 5. find the percentage change in the result due to this mistake. 96% 95% 2400% None of these
Q11 . A no. is mistakenly divided by 5 instead of being multiplied by 5. find the percentage change in the result due to this mistake.96%95%2400%None of these
dividing by 5 number will be x/5 multiplying by 5 number will be 5x %age Error = (True value - False Value)*100/True Value = (5x - x/5)100/5x = 24x X 100/25x = 96%
Let the no. be x dividing by 5 number will be x/5multiplying by 5 number will be 5x %age Error = (True value - False Value)*100/True Value= (5x - x/5)100/5x= 24x X 100/25x= 96%
