600 students took test on physics & chemistry.35 %failed in phy. and 45% failed in chem. and 40% of dose who passed in chem also passed in phy.,,den hw many student failed in both ???
@shubhrans1 said:600 students took test on physics & chemistry.35 %failed in phy. and 45% failed in chem. and 40% of dose who passed in chem also passed in phy.,,den hw many student failed in both ???
12 ??
Check post 5129, explained the aproach
http://www.pagalguy.com/forums/quantitative-ability-and-di/official-quant-thread-cat-2011-part-2-t-67094/p-2761065/r-2815978?page=257
@shubhrans1 said:@shattereddream 12 is corrrect plz share the approach.
No. of students who took the test = 600
No. of students who failed in Physics ie 0.35 x 600 = 210
Then No. of students who passed in physics = 390
No. of students who failed in chemistry=0 .45 x 600 = 270
Then No. of students who passed in Chemistry = 330
No. of students who Passed in both = 0.4 x 330 = 132
No. of students who failed in both = 600 - (330 + 390 - 132) = 12
No. of students who failed in Physics ie 0.35 x 600 = 210
Then No. of students who passed in physics = 390
No. of students who failed in chemistry=0 .45 x 600 = 270
Then No. of students who passed in Chemistry = 330
No. of students who Passed in both = 0.4 x 330 = 132
No. of students who failed in both = 600 - (330 + 390 - 132) = 12
@shattereddream said:No. of students who took the test = 600No. of students who failed in Physics ie 0.35 x 600 = 210Then No. of students who passed in physics = 390No. of students who failed in chemistry=0 .45 x 600 = 270 Then No. of students who passed in Chemistry = 330No. of students who Passed in both = 0.4 x 330 = 132No. of students who failed in both = 600 - (330 + 390 - 132) = 12
I've one more approach.
35% failed in physic means 65% passed. similarly 45% failed in Chem means 55% passed. Now 40% of 55% passed in chem also passed in phy i.e. 22%( Passed in both).
so final solution
failed in phy and chem = passed in phy + passed in chem - passed in phy & chem
= 65+55-22 =2%
2%of 600 = 12.
@shubhrans1 yes, it is done using Venn diagram.
35% failed in physic means 65% passed. similarly 45% failed in Chem means 55% passed. Now 40% of 55% passed in chem also passed in phy i.e. 22%( Passed in both).
so final solution
failed in phy and chem = passed in phy + passed in chem - passed in phy & chem
= 65+55-22 =2%
2%of 600 = 12.
@shubhrans1 yes, it is done using Venn diagram.
ON what date of march 1893 did friday fall ?
@katty021 said:ON what date of march 1893 did friday fall ?
1600 years give no odd days
200 years give 3 odd days
92 years give (92 + 23 ) or 3 odd days
Thus 1892 years give 6 odd days
From 1st January to 1st March there are 4 odd days
Thus the total number of odd days = 6 + 4 or 3 odd days
This means that the 1st of March fell on 3rd day commencing from Monday. Means on Wednesday.
So 1st friday of march will be on 3rd
What is OA??
200 years give 3 odd days
92 years give (92 + 23 ) or 3 odd days
Thus 1892 years give 6 odd days
From 1st January to 1st March there are 4 odd days
Thus the total number of odd days = 6 + 4 or 3 odd days
This means that the 1st of March fell on 3rd day commencing from Monday. Means on Wednesday.
So 1st friday of march will be on 3rd
What is OA??
Hey guys, could anyone let me know what the time limit for each block review test(1-7) is??? Arun Sharma wants us to complete each test inside the "Time Limit" , but somehow has not mentioned what the time should be... Thanks.
@sajin123 said:Hey guys, could anyone let me know what the time limit for each block review test(1-7) is??? Arun Sharma wants us to complete each test inside the "Time Limit" , but somehow has not mentioned what the time should be... Thanks.
for RT1 it is given as 30 mins . SO you can assume the same for all 😃 I hope that is not something that should be worried of.
@sajin123 said:Hey guys, could anyone let me know what the time limit for each block review test(1-7) is??? Arun Sharma wants us to complete each test inside the "Time Limit" , but somehow has not mentioned what the time should be... Thanks.
for RT1 it is given as 30 mins . SO you can assume the same for all 😃 I hope that is not something that should be worried of.
@chandrakant.k said:for RT1 it is given as 30 mins . SO you can assume the same for all I hope that is not something that should be worried of.
Thanks Chandrakant :)
@vbhvgupta 1600 years give no odd days
200 years give 3 odd days..i dnt get this can y explain ..plz...!
200 years give 3 odd days..i dnt get this can y explain ..plz...!
@katty021 said:@vbhvgupta1600 years give no odd days200 years give 3 odd days..i dnt get this can y explain ..plz...!
@katty021 every 100 years has 1 odd day 200 years has 3 odd days n 400 years have 7 odd days which is effectively the same day of the week so it is regarded as 0 odd day. Hope i was able to clear your doubt
@katty021 said:@vbhvgupta1600 years give no odd days200 years give 3 odd days..i dnt get this can y explain ..plz...!
In a given period, the number of days more than the complete weeks are called odd days.
like for 49 days 49/7 = 0 odd days
58 days 58/7 = 2 odd days
300 days 300/7 = 6 odd days(basically remainder when divided by 7)
1 ordinary year = 365 days = (52 weeks + 1 day.)
1 ordinary year has 1 odd day.
1 leap year = 366 days = (52 weeks + 2 days)
1 leap year has 2 odd days.
100 years = 76 ordinary years + 24 leap years
= (76 x 1 + 24 x 2) odd days = 124 odd days.
= (17 weeks + 5 days) 5 odd days.
Number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) 3 odd days.
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.
Hope this will help.
1 ordinary year has 1 odd day.
1 leap year = 366 days = (52 weeks + 2 days)
1 leap year has 2 odd days.
100 years = 76 ordinary years + 24 leap years
= (76 x 1 + 24 x 2) odd days = 124 odd days.
= (17 weeks + 5 days) 5 odd days.
Number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) 3 odd days.
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.
Hope this will help.
Q10 . Brass is an alloy of copper and zinc. Bronze is an alloy containing 80% of copper, 4% ofzinc and 16% of tin. A fused mass of brass and bronze is found to contain 74% of copper,16% of zinc and 10% of tin. The ratio of copper to zinc in brass is:
64 and 36
33 and 67
50 and 75
35 and 65
None of these
64 and 36
33 and 67
50 and 75
35 and 65
None of these
Q2 . The duration of a railway journey varies as the distance and inversely as the velocity, the velocity varies directly as the square root of the quantity of coal used per kilometer , and inversely as the number of carriages in the train. In a journey of 50 km in half an hour with 18 carriages, 100 kg of coal is required . How much coal will be consumed in a journey of 42km in 28 min with 16 carriages.
a. 53.76
b. 179.33
c. 47.51
d. 48.43
e. None of these
a. 53.76
b. 179.33
c. 47.51
d. 48.43
e. None of these
Q28 . A tank of 425 liters capacity has been filled with water through two pipes, the first pipe having been opened 5 hours longer than the second. If the first pipe were open as long as the second pipe; if the two pipes were open simultaneously, the tank would be filled up in 17 hours. How long was the second pipe open?
a. 10
b. 12
c. 15
d. 18
a. 10
b. 12
c. 15
d. 18
Q28 . A tank of 425 litres capacity has been filled with water through two pipes, the first pipe having been opened 5 hours longer than the secong. If the first pipe were open as long as the second pipe; if the two pipes were open simultaneously, the tank would be filled up in 17 hours. How long was the second pipe open?
a. 10
b. 12
c. 15
d. 18
a. 10
b. 12
c. 15
d. 18