Trying with the second one... I think you have framed the question wrong... i have taken as: mth term as 1/n nth term as 1/m and we need to find sum upto mn terms
so, S(mn)= mn/2(2a + (mn-1)d) ----> 1
we will substi the value of a and d from the equations below:
a+(m-1)d = 1/n a+(n-1)d = 1/m
now subtracting
we get d= 1/mn put the value in any one of the equations we get the value of a = 1/mn
Hey can you please recheck the question. See this is how I approached the problem and I am getting the answer as 20. Check out my method and point out any mistakes that you find.
Let us consider that arun(A) ,bikas(B) and chetakar(C) each have a, b, c respectively initially
after A gives the coin to B and C. B and C will each have 3 times what they had initially and A that much less. A: a - 2b - 2c B: 3b C: 3c
After B gives the coins, A: 3(a - 2b - 2c ) B: 3b - 2*(3c) - 2*(a - 2b - 2c ) -------(1) C: 3*(3c)
see we can break the 180 as 45*4 and taking the pairs of (20^41 + 25^41)+ (22^41 +23^41) + (24^41 + 21^41) and as we know that each term is of the form a^n+b^n and it will give a factor of (a+b) hence we can eaisly conclude that 45 is a common factor among all the terms hence on dividing by 45 the remiander is 0.
also taking the individual terms and dividing them by 4 we get 3 as remainder as 20^41 and 24^41 gives remainder as 0 21^41 and 25^41 gives remainder as 1...
and 22^41 gives remainder as 2 and 23^41 remainder as 3 summing all up and taking the final remainder we get 7 mod 4 = 3
now our task is to find the reaminder by division of 45*4 where individual remainders are 0 and 3 respectively
applying chinese remainder theorm we get 45*1*3-11*1*0= 135 thats the remiander
Originally Posted by AnkitaKayal View Post Hey can you please recheck the question. See this is how I approached the problem and I am getting the answer as 20. Check out my method and point out any mistakes that you find.
Let us consider that arun(A) ,bikas(B) and chetakar(C) each have a, b, c respectively initially
after A gives the coin to B and C. B and C will each have 3 times what they had initially and A that much less. A: a - 2b - 2c B: 3b C: 3c
After B gives the coins, A: 3(a - 2b - 2c ) B: 3b - 2*(3c) - 2*(a - 2b - 2c ) -------(1) C: 3*(3c)
at burger king- a famous fast food center on main street in Pune,burgers r made only on an automatic burger making machine.d machine conntinuously makes different sorts of burger by adding different sorts of filling. d machine makes burger at d rate of 1 burgers per half minute.the various fillings are added in d following manner. the 1st,5th,9th.... burgers r filled with chicken patty; d 2nd,9th,16th.... burgers with vegetable patty ; d 1st,5th,9th.... burgers with mashroom patty and the rest with plain cheese and tomato fillings. d machine makes exactly 660 burgers per day
1) how many burgers per day are made with cheee n tomato fillings a) 424 b) 236 c) 237 d) none of these
at burger king- a famous fast food center on main street in Pune,burgers r made only on an automatic burger making machine.d machine conntinuously makes different sorts of burger by adding different sorts of filling. d machine makes burger at d rate of 1 burgers per half minute.the various fillings are added in d following manner. the 1st,5th,9th.... burgers r filled with chicken patty; d 2nd,9th,16th.... burgers with vegetable patty ; d 1st,5th,9th.... burgers with mashroom patty and the rest with plain cheese and tomato fillings. d machine makes exactly 660 burgers per day
1) how many burgers per day are made with cheee n tomato fillings a) 424 b) 236 c) 237 d) none of these
Hi if the values given in the question are correct i.e. there is no typo,which i feel strongly is the case,the answer should be 400 and so,none of these.
Hi if the values given in the question are correct i.e. there is no typo,which i feel strongly is the case,the answer should be 400 and so,none of these.
also taking the individual terms and dividing them by 4 we get 3 as remainder as 20^41 and 24^41 gives remainder as 0 21^41 and 25^41 gives remainder as 1...
and 22^41 gives remainder as 2 and 23^41 remainder as 3 summing all up and taking the final remainder we get 7 mod 4 = 3
Hi shivam, When 22^41 is divided by 4,the remainder should be 0,as the two 2's in two 22's cutoff the 4,right?So i am getting the remainder as 1 and subsequently the answer as 45.Please explain me if i am making a mistake somewhere. Thanks.
In that case,the condition in the question could be that if a burger contains more than 1 filling,the machine chooses to give it none of them but plain cheese and tomato. If we consider all there cases,we can find 24 of them as 9,37,65....653. Add this 24 to the 400 and we get 424 which is the answer.
Solve these Questions on Man, hour & work.........
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@loveena Nice questions. My take on the answers, 1)15 days 2)144 hours 3)42 days 4)55 days 5)345 Rs 6)10 days 7)108 days Will post detailed answers if they are correct 😃
