Quant by Arun Sharma

MBA CAT 2022
792
@loveena
Nice questions.
My take on the answers,
1)15 days
2)144 hours
3)42 days
4)55 days
5)345 Rs
6)10 days
7)108 days
Will post detailed answers if they are correct :-)

All your answers are correct except for the 6th question....

Ans6) Total food in the fort : 200 * 31= 6200 units
food consumed in 27 days: 27 * 200= 5400 units

food left = 6200-5400= 800 units
120 soldiers left the fort after 27 days, so remaining soldiers are 80.

Now food's left for (800/80) days i.e. 10days

But soldiers consumed food for 28th 29th 30th & 31st dayi.e. 4 days
Hence the number of extra days for which the food lasts for remaining soldiers is : 10-4= 6 days

6 days is the correct answer.

Pls explain other answers in detail, especially Q2,3,5 & 7
793

Hi loveena,
Yeah,that was my mistake in reading the question.
You are right.I just left the answer at the penultimate step.
Detailed explanations for answers-
1)Let the 5 workers leave the job after x days.
Now,from the question,
20 workers:30 days.
So in 1 day,1 worker does 1/600 of the work.
So,total work done is,
20x/600+15(35-x)/600=1
On solving,x=15
2)let manoj take a hrs to finish the work.So,in 1 hr,he does,
1/a part of work.
So,ajay takes a/2 hrs.so if does 2/a part of work in 1 day.vijay takes a/3 hrs to finish the work.so,in 1 hr if does 3/a part of the work.
In 24 hrs,
24/a+48/a+72/a=1
So,a=144 hrs.
3)let vijay take x days to complete the job,
So,in 14 days,he does
14/x part of the job.
Raju is twice as good as vijay.so he finishes the job in x/2 days.
In 14 days,he does,28/x part of the job.
Now,
14/x+28/x=1
So,x=42.
4)15 men take 210 days to complete the job.
In 1 day they do 1/210 part of the work.
In 100 days,they do
100/210 of the job.
So,remaining part is
110/210
Now,15 more men,so 30 men.so job done in a day is 1/105.
Let they do the job for x days.
So,work done is x/105.
But work to be done was,
110/210
On equating,
x=55 days.
5)ajay and vijay do 19/23 of the work together,so they should be paid,
437 rs.let ajay's share be a and vijay's share be v.Also,vijay and sanjay do 8/23 of the work,so,
184 rs.
On addition,
a+2v+s=621.
But,
a+v+s=529.
So,v=92,
So,a=345rs.
6)as you said ;-)
7)C takes x days to finish work.
So,in 1 day,it does,1/x of work.
Similarly,for B and A,the figure is 1/y and 1/z respectively.
So,1/x+1/y+1/z=1/36
According to the condition,
1/y+1/z=2/x
So,3/x=1/36
So,x=108 days.

Btw did you see the qqad thread for today?You will like the sum.
Keep posting,
All d best.

794

2nd edition
geomerty
lod-II
anyone knows how to solve
q19(circle with 19degree)
q21(2 intersecting circles and a tangent CD)
q22(2 intersecting circles with 2 direct common tangents and a chord)

795

Hi aditya,
It would help if you could post the question here.I might just be able to solve it.I dont have arun sharma 😞

796

Q19.if a circle is provide with a measure of 19degree on centre,is it posiible to divide the circle into 360 equal parts?
ans--always

Q21.two circles C(o,r) and C(o',r') intersect at two points A and B and o lies on C(o',r').a tangent CD is drawn to second circle at A.then:
ans--

797

Time & Work, lod2:
Mini and vinay are quiz masters preparing for a quiz. in x minutes, Mini makes y questions more than vinay. If it were possible to reduce the time needed by each to make a question by two minutes, then in x minutes Mini would make 2y questions more than vinay. How many questions does Mini make in x minutes?
a) 1/4
b) 1/4
c) either a or b
d)1/4
e) none of these
thanks in advance.

798

Are there any shortcuts for division for the problems asked in data interpretation in the CAT papers.

Regards,
Uday Padhye.

799

x,y,z are three positive integers such that x>y>z.Which of the following is closest to the product xyz

a) (x-1)yz b)x(y-1)z c)xy(z-1)

and how??

800

@arora-I would advise that in this kind of questions,you put values in place of x,y,z such that they satisfy the conditions.
In this case,you can take 2,3,4 as the nos.If we take xyz its 24.If we remove 1 from 4 i.e. The largest integer,we get the answer the closest to the original.
So,option(1)
In any case,if you remove a quantity from a larger item and similar quantity from a smaller item,the resultant quantities still stand the same equality.
Hope that helps.

801

THE greatest no which will divide 4003,4126,4249 leaving the same remainder in each case
a)43 b)41 c)45

please tell how to attack these types..!!

802
THE greatest no which will divide 4003,4126,4249 leaving the same remainder in each case
a)43 b)41 c)45

please tell how to attack these types..!!

directly hcf of those vil giv u ans...
orels
take difference of those nd find hcf....coz,hcf wont change..

now,hcf(4126-4003,4249-4126)
hcf(123,123) = 41( highest prime factor)
803
THE greatest no which will divide 4003,4126,4249 leaving the same remainder in each case
a)43 b)41 c)45

please tell how to attack these types..!!



I would advise you to check for all the nos.But this does not mean that you have to know the tables of 41,43 and 45.For 41 and 43, i would find the difference between the nos and 4100 and 4300 respectively.
For 45,it would be better if you consider 4275.
So,the answer is 41 which leaves a remainder of 26.Also,i would advise you to start with 45 as they have asked for the largest no.If you get answer as 41,you will have to do it for 43 awa 45.
804

Originally Posted by arora1142 View Post
THE greatest no which will divide 4003,4126,4249 leaving the same remainder in each case
a)43 b)41 c)45

please tell how to attack these types..!!


Directly take the HCF of difference of numbers

HCF(4126-4003,4249-4126)

HCF (123,123) = 123 since 123= 41*3 hence 41
805

Hi everyone, was going through previous aimcats today. I encountered these two questions. Since this thread is more active than the aimcat one, we could come up with a solution a lil faster. Can anyone help me out with these? Thanks :)


Q- Grant, the Ant crawled two miles north, then one mile east, then half a mile south, then one-fourth mile west, one-eighth mile north, one-sixteenth mile east, and so on indefinitely. The point at which Grant converged (where it found itself going around in circles) was how far from the starting point?

1) 4/ 5 miles
2) 6/ 5 miles
3) 5 miles
4) 22 miles
5) None of these


Q2. Let R1 and R2 respectively denote the maximum and minimum possible remainders when (276) ^n is divided by 91, for any natural number n, n>=144. Find R1 + R2.
1) 90
2) 108
3) 84
4) 64
5) 82

806
Hi everyone, was going through previous aimcats today. I encountered these two questions. Since this thread is more active than the aimcat one, we could come up with a solution a lil faster. Can anyone help me out with these? Thanks :)


Q- Grant, the Ant crawled two miles north, then one mile east, then half a mile south, then one-fourth mile west, one-eighth mile north, one-sixteenth mile east, and so on indefinitely. The point at which Grant converged (where it found itself going around in circles) was how far from the starting point?

1) 4/ 5 miles
2) 6/ 5 miles
3) 5 miles
4) 22 miles
5) None of these


Q2. Let R1 and R2 respectively denote the maximum and minimum possible remainders when (276) ^n is divided by 91, for any natural number n, n>=144. Find R1 + R2.
1) 90
2) 108
3) 84
4) 64
5) 82


1) 4/ 5 miles srry earlier i did a lil mistake wasnt considering vertical annd horizontal displacement
2) 82 😃
807
Hi everyone, was going through previous aimcats today. I encountered these two questions. Since this thread is more active than the aimcat one, we could come up with a solution a lil faster. Can anyone help me out with these? Thanks :)


Q- Grant, the Ant crawled two miles north, then one mile east, then half a mile south, then one-fourth mile west, one-eighth mile north, one-sixteenth mile east, and so on indefinitely. The point at which Grant converged (where it found itself going around in circles) was how far from the starting point?

1) 4/ 5 miles
2) 6/ 5 miles
3) 5 miles
4) 22 miles
5) None of these




I got the answer as 1)4/sqrt(5)
will post the approach if this is correct. Please post the answer
808
Hi everyone, was going through previous aimcats today. I encountered these two questions. Since this thread is more active than the aimcat one, we could come up with a solution a lil faster. Can anyone help me out with these? Thanks :)


Q- Grant, the Ant crawled two miles north, then one mile east, then half a mile south, then one-fourth mile west, one-eighth mile north, one-sixteenth mile east, and so on indefinitely. The point at which Grant converged (where it found itself going around in circles) was how far from the starting point?

1) 4/ 5 miles
2) 6/ 5 miles
3) 5 miles
4) 22 miles
5) None of these



I don't know the correct answer but atleast it will be between option 1 and 5, as it can be easily said that answer will lie between 1 and 2 as vertical distance will be less than 2 and more than 1; horizontal distance will be less than 1 and when we will apply pythagoras in two number, one between 1 and 2, other less than 1; answer will difinitely lie between 1 and 2

Answer = (sqrt((1.x)^2 + (.y)^2))

Now someone give the right approach to reach to the correct answer.
809

If we calculate the total displacement vertically it would be
2 -1/2 + 1/8 - 1/32 ....
Total horizontal displacement is 1 - 1/4 + 1/16 ....
Both these are GP to inifinite terms. so S1= 2/(1+1/4) =8/5
S2=4/5

So the displacement in total =sqrt ( 64/25+16/25) =4/sqrt(5)

810

hey everyone, posting the answers now. just for reference, these questions were asked in aimcat 917.

for Q 1, answer is option (1) 4/ 5 miles. I was going through the solutions provided, both here and in the key,i noticed the minus sign because of vertical displacement- but still trying to understand it.

for Q2, answer is option (5) 82.

it's great to see how ppl are so approachable here on PG. thanks for all your help. will post again if any further doubts arise:)

811
hey everyone, posting the answers now. just for reference, these questions were asked in aimcat 917.

for Q 1, answer is option (1) 4/ 5 miles. I was going through the solutions provided, both here and in the key,i noticed the minus sign because of vertical displacement- but still trying to understand it.

for Q2, answer is option (5) 82.

it's great to see how ppl are so approachable here on PG. thanks for all your help. will post again if any further doubts arise:)

Thanks Wordsmith
in between can u post the solution or answers to the questions posted on the Quant thread please