hiee...
need a help in solving a question...
The digits of a two digit number differ by 3. Find the difference between the number and the number obtained by reversing its digits.
Thanks
Priyesh
:
hey can someone pls solve the foll ques for me..
p&c; LOD2
q30. a train is running between patna to howrah. 7 ppl enter the train somewhere b/w the 2 cities. 9 stops are there in b/w the 2 cities. in how many ways can the tickets be purchased if no restriction is there with respect to the number of tickets at any station?
hey can someone pls solve the foll ques for me..
p&c; LOD2
q30. a train is running between patna to howrah. 7 ppl enter the train somewhere b/w the 2 cities. 9 stops are there in b/w the 2 cities. in how many ways can the tickets be purchased if no restriction is there with respect to the number of tickets at any station?
is it 45C7
hiee...
need a help in solving a question...
The digits of a two digit number differ by 3. Find the difference between the number and the number obtained by reversing its digits.
Thanks
Priyesh:
Let the number be xy.
The difference in the digit according to the question is x-y=3
Again acc. to the problem 10x+y-(10y+x).....we need to find out
this equation gives 10x+y-10y-x
which is 9x-9y
=>9(x-y)
=>9*3
=>27.
shanks4mba Saysis it 45C7
yes..can u pls elaborate on it?
rachitabehl Saysyes..can u pls elaborate on it?
as there are 10 stops...the total no. of different tickets from one station to another will be 45....this can be calulated as follows...there can be 9 different tickets purchased from the 1st stop to the rest 9 stops similarly 8 different tickets from 2nd stop...therefore...total no. of different tickets = 9 + 8 + 7 + 6 + 5+ 4+3+2+1 = 45...
now you need to select 7 out of them...as 7 plp are getting in, therefore its 45C7
Hi all
Can anyone explain the following qs to me!
Chapter 8, LOD3, Qs 4
Hi all
Can anyone explain the following qs to me!
Chapter 8, LOD3, Qs 4
pls post the quest along with the other details this will help the puys who are nt having arun sharma too solve these problems...
People,,
How effective do you think is doin the LOD3 of Quants by Arun Sharma for CAT?
Yeah....LOD-3, as explained by Mr.Sharma is of the highest possible difficulty level and so it trains you for the 10-20% above average (or say 'impossible' qus.) that comes in CAT.. the good news is that you need not to solve them in CAT and so you may also skip LOD-3 in prep!!..
Here my doubt...
Q)Which of the following is not a perfect square?
100856,325137,945729,All of these,None of these....
So,the query is that traditional way says to find their prime factors and then conclude..But that process is very tedious..N I seek some short method....
Do Anyone know any shortcut?..
Yeah there are two methods that you may consider as' shortcuts'.... one look out for any factor of number that is not coming in pair (this is a bit tedious one),, the other is to have an approx square root of the numbers given n then check if no no. is repeated more than once.. (Note: best wud be to leave such qus. in Cat!)
Here my doubt...
Q)Which of the following is not a perfect square?
100856,325137,945729,All of these,None of these....
So,the query is that traditional way says to find their prime factors and then conclude..But that process is very tedious..N I seek some short method....
Do Anyone know any shortcut?..
If you're looking for a single number, then this is pretty simple and the answer is 325137, simply because no square can end in 2, 3, 7 or 8 😃 However, I find that none of the numbers are squares. The 3n and 3n+1 method is okay but not fool proof as many numbers follow this rule but are not squares, as someone earlier suggested correctly. By that method, you can infer that 100856 is not a square but you can't be sure of 945729.
So in such a situation, you have to find out the prime factors. But of course, since two numbers are already not squares, you can safely mark "All of these" 😃
hiee...
need a help in solving a question...
The digits of a two digit number differ by 3. Find the difference between the number and the number obtained by reversing its digits.
Thanks
Priyesh
Apart from the algebraic solution mentioned by someone earlier, I would suggest you to take an example in such a question.
Take any number which has a digit and digit+3 as its two digits. Suppose, 14. So, 41-14 = 27
Now, if it's 25. Then, 52-25 = 27
Similarly, 58. 85-58 = 27
So, no matter which number you choose, the difference will always be 27. This method is much faster than solving algebraically.
no...sorry that was for cubes and actually not 3m+ 8 but 9m+8...mistake ho gayi yr!!
Hello! I am new to PG and I am already lovin' it :)
Here's my question:
1. The square of a number greater than 1000 that is not divisible by 3, when divided by 3, leaves a remainder of
a)1 always
b)2 always
c)Either 1 or 2
d)Cannot be said
2. Find the LCM of (x+3)(6x2+5x+4) and (2x2+7x+3)(x+3)
a)(2x+1)(x+3)(3x+4)
b)(4x2-1)(x+3)2(3x+4)
c)(4x2-1)(x+3)(3x+4)
d)(2x-1)(x+3)(3x+4)
For the second question, I have a feeling that the answer is wrong. Plz confirm.
Thanks!
Hello! I am new to PG and I am already lovin' it :)
Here's my question:
1. The square of a number greater than 1000 that is not divisible by 3, when divided by 3, leaves a remainder of
a) 1 always
b) 2 always
c) Either 1 or 2
d) Cannot be said
2. Find the LCM of (x+3)(6x2+5x+4) and (2x2+7x+3)(x+3)
a) (2x+1)(x+3)(3x+4)
b) (4x2-1)(x+3)2(3x+4)
c) (4x2-1)(x+3)(3x+4)
d) (2x-1)(x+3)(3x+4)
For the second question, I have a feeling that the answer is wrong. Plz confirm.
Thanks!
1. A number greater than 1000 and not divisible by 3 will leave a remainder of 1 or 2. So, its square will leave a remainder of 1*1 or 2*2 i.e. 1 or 4. 4 cannot be a remainder as 3 is the divisor. So, the remainder can only be 1.
2. Option b is the answer. put x=0 and the numbers are 12,9. LCM = 36. Only option b fits.
PS : The next time you post a question, kindly write x square as x^2 and not x2...makes it a lot easier to comprehend
1. A number greater than 1000 and not divisible by 3 will leave a remainder of 1 or 2. So, its square will leave a remainder of 1*1 or 2*2 i.e. 1 or 4. 4 cannot be a remainder as 3 is the divisor. So, the remainder can only be 1.
2. Option b is the answer. put x=0 and the numbers are 12,9. LCM = 36. Only option b fits.
PS : The next time you post a question, kindly write x square as x^2 and not x2...makes it a lot easier to comprehend
Thanks a lot!
can someone pls help me out with these ques?
1) the latest registraton no issued by the delhi motor vehicle registration authority is dl-5S 2234. if all the numbers and alphabets before this have been used up then find how many ehicles have a registration no starting with dl-5?
ans. 182216
2) seven different objects must be divided among 3 ppl. in how many ways can this be done if one or two of them can get no objects?
ans. 2187
3) in a building there are 12 floors plus the ground floor. 9 ppl get into the lift of the building on the ground floor. the lift doesn't stop on the first floor. if 2,3 and 4 ppl alight from the lift on its upward journey then in how many ways can they do do?(assuming they alight on different floors)
ans. 11p3*9c4*5c3
pls explain the answer! thanks in advance!
can someone pls help me out with these ques?
1) the latest registraton no issued by the delhi motor vehicle registration authority is dl-5S 2234. if all the numbers and alphabets before this have been used up then find how many ehicles have a registration no starting with dl-5?
ans. 182216
pls explain the answer! thanks in advance!
1 .for registration starting from ds-5a0001 to ds5a9999 there are 9999 nos. similarly this goes from a to r i.e total 18 alphabets therefore total no of nos. will be 18 * 9999 = 179982 plus you have 2234 nos. for the letter s so total is 179982 + 2234 = 182216
Hey guys,
PLease let me know any online source of downloading Arun Sharma's book for Quant!
Hey guys,
PLease let me know any online source of downloading Arun Sharma's book for Quant!
AFAIK, there is no online source..you gotta spend the moolah !
