CHSL & FCI PREPARATION

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952

@pavi.k said:
general intelligence:
1) 08:18::24:?
a) 38
b) 32
c) 44
d) 43
3^2-1 : 4^2+2 :: 5^2-1 : 6^2+2

38
953

bhai logo ye batao ki last ten year ke papers kahan se milenge for chsl......??? ........as only last 10 days are left..............pls reply soon.........

954
@pavi.k said:
general intelligence:
1) 08:18::24:?
a) 38
b) 32
c) 44
d) 43
iska answer 38 hoga
3^2 -1
4^2+2
5^2-1
6^2 +2=38
955
@pavi.k said:
2) 6:35::9:?
a) 18
b) 27
c) 53
d) 72
52

6*6-1= 35
9*6-1=53
956
@pavi.k said:
Select the one which is diff from the other 3 responses
3) a) 3216 b) 2338 c) 3205 d) 2015
4) a) 441 b) 256 c) 361 d) 481
4) 481 all other are squares

3)3025
957
@custom said:
4) 481 all other are squares
3)3025
Bhai, please give the explanation for Question 3. How 3205?
958
@pavi.k said:
Select the one which is diff from the other 3 responses
3) a) 3216 b) 2338 c) 3205 d) 2015
4) a) 441 b) 256 c) 361 d) 481
3.

3+2+1 = 6
2+3+3=8
3+2+0=5
2+0+1 not equal to 5

ans d)

4.

21^2=441
16^2=256
19^2=361
481 not perfect square
ans d)
959
@pavi.k said:
Select the one which is diff from the other 3 responses
3) a) 3216 b) 2338 c) 3205 d) 2015
4) a) 441 b) 256 c) 361 d) 481
qus 1 has three different ans. 1. 3216 because sirf yahi 3 se divisible hai

2. 2015 because isne 2+0+1=3 hai last digit 5 nahi jabki baki sab me 3+2+1=6 , 2+3+3=8, 3+2+0=5 hai

3. 2338 because sirf isi ka digit sum perfect square hai 2+3+3+8=16
960

select the one which is diff from other responses:

1) a)46,24
b) 62,32
c) 56,30
d) 74,38

2) a) RPSZ
b) AIUE
c) QRTM
d) NQMR
961

Complete the series:

1) 30,68,130,222,-------,520,738
a)420
b)350
c)205
d)280
962

find the wrong num in the series

225, 336, 447, 555, 669
963
find the wrong num in the series
225, 336, 447, 555, 669

As in all other digits are repeating twice in continuous and in 555, something fishy it seems... also, 22, 33,44,55,66..series is followed.... and so does 5,6,7,...9... we got wrong fish in the pond is 555. which should be 558, i guess..
964
select the one which is diff from other responses:
1) a)46,24
b) 62,32
c) 56,30
d) 74,38


24 *2 -2 = 46
32*2-2 = 62
30*2- 2= hehahahahaha..buhahha
38*2-2 = 74

so...hehahaha..buhahhaaa..is the answer...we needed..

2) a) RPSZ
b) AIUE
c) QRTM
d) NQMR

vowel/consonant thing it seems....AIUE...in others there is no single vowel is there..
965
@pavi.k said:
Complete the series:
1) 30,68,130,222,-------,520,738
a)420
b)350
c)205
d)280
concept ..heheeee... I m far behind the concept...

205 cant be option as series is ascending...

280...difference in between two numbers should be more than that which we getting from 280...

420...as difference between 222 and 130 already reached near of 100..this cant be the option...

350 fits all....so my take 350
966
@anticipator.lad
:) LOGICAL ANS EH..
try finding how the series is arranged...
967

@pavi.k said:
@anticipator.lad
LOGICAL ANS EH..
try finding how the series is arranged...
Three steps of 'successive difference in between two digits' giving same digit 6 by putting 350... its long procedure... 😞
968
@anticipator.lad
HA.. i too tried the same.. there may be some other relation i suppose
969
@anticipator.lad said:
Facts to remember:-
1) (a^n - b^n) will always be divisible by (a-b).
2) (101^1 - 1) to (101^9 - 1) will be divisible by 100
(101^10 - 1) to (101^99 - 1) will be divisible by 1000,
therefore (101^100 - 1) will be divisible by 10,000.
These questions are commonly asked, so its best to remember these 2 facts.
Brother, I do not agree with your explanation.
What i see in here is that divisibility factor is dependent on "n", but according to me it is independent of the power.
a^n-b^n is always divisible by a-b, irrespective of "n" and will be divisible by a+b when "n" is even.
What's your take?
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@harshsingal27 said:
Brother, I do not agree with your explanation.
What i see in here is that divisibility factor is dependent on "n", but according to me it is independent of the power.
a^n-b^n is always divisible by a-b, irrespective of "n" and will be divisible by a+b when "n" is even.
What's your take?
a^n-b^n is always divisible by a-b, irrespective of "n" and will be divisible by a+b when "n" is even- Yes, that is what i read in some book and now forgot its name.

Yes bro, you are right...but here i gave explanation according to the question and options posted with the "largest divisible" factor. And for that two conditions:- (a^n - b^n) considering (a-b ) factor and also with how 10000 is largest, i provided the answer....as in related of (a+b), none of the options have been provided with 101+1= 102 thingy... so i ruled it out in giving explanation. Have i done something wrong in this?

please yaar wo book ka naam bata do...jaha pe ye concept tha jo maine bold mein likha hai..i need to read it again..
971
@anticipator.lad said:
a^n-b^n is always divisible by a-b, irrespective of "n" and will be divisible by a+b when "n" is even- Yes, that is what i read in some book and now forgot its name.
Yes bro, you are right...but here i gave explanation according to the question and options posted with the "largest divisible" factor. And for that two conditions:- (a^n - b^n) considering (a-b ) factor and also with how 10000 is largest, i provided the answer....as in related of (a+b), none of the options have been provided with 101+1= 102 thingy... so i ruled it out in giving explanation. Have i done something wrong in this?
please yaar wo book ka naam bata do...jaha pe ye concept tha jo maine bold mein likha hai..i need to read it again..
Brother, since we are not given any information about "n"(even or odd), we can only take a-b to be a 'certain' factor of given expression, so answer according to me would be 101-1=100

The book is our beloved M.Tyra