Q1: Are x and y both positive? 1) 2x-2y=1 2) x/y >1
C
Q2: Is m+z>0 ? 1) m-3z>0 2) 4z-m>0
E
Q3: If integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of an, what is the value of a? 1) an = 64 2) n = 6 E
Q4: What is the remainder when posiytive integer x is divided by 6? 1) When x is divided by 2, the remainder is 1; and when x is divided by 3, the remainder is 0.( try numbers 9,13) 2) When x is divided by 12, the remainder is 3.
B
Q5: At a certain company, average (aritmetic mean) number of years of experience is 9.8 years for male employees and 9.1 years for female employees. What is the ratio of the number of company's male employees to the number of company's female employees? 1) There are 52 male employees at the company. 2) Average number of years of experience for the company's male and female employees combined is 9.3 years. C
Q1: Are x and y both positive? 1) 2x-2y=1 2) x/y >1
Q2: Is m+z>0 ? 1) m-3z>0 2) 4z-m>0
Q3: If integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of an, what is the value of a? 1) an = 64 2) n = 6
Q4: What is the remainder when posiytive integer x is divided by 6? 1) When x is divided by 2, the remainder is 1; and when x is divided by 3, the remainder is 0. 2) When x is divided by 12, the remainder is 3.
Q5: At a certain company, average (aritmetic mean) number of years of experience is 9.8 years for male employees and 9.1 years for female employees. What is the ratio of the number of company's male employees to the number of company's female employees? 1) There are 52 male employees at the company. 2) Average number of years of experience for the company's male and female employees combined is 9.3 years.
reasonong for sum 4 and sum 5 :
Prob 4:
we need to epress the no in the form 6k+m, where k and m are integer values and we need one definite value for m..
St 1 : no is odd multiple of 3 ....hence of the form 6k+3 ...one definite remainder 3 ...hence sufficient..
St2: no is of the form 12p+3 i .e 6*2*p +3 i.e 6k+3 ( where k =2p)...hence again one def remainder 3 ...sufficient ...
Hence, Ans D
Prob 5:
let there be x male and y female employees.. so, total experience = 9.8x +9.1y... we need one more equation to get values of x and y for a specific ratio of x/y
St 1: x =52....still neither we dont know the total employee strength nor total experience...not suff..
St 2: total experience = 9.3 (x+y) so, 9.3 (x+y) = 9.8x +9.1y.. Hence, x/y = 2/5 ...suff
I was about to put my explanation for 5th problem as I felt C is not the right answer. Glad that you found the mistake in your earlier post all by yourself.
Thanks for the explanation. Your answers are correct except for Q3 which had a typo. The question goes as below: Q3: If integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of an, what is the value of a? 1) a^n = 64 2) n = 6 Can you please give your answer and explanation?
Thanks for the explanation. Your answers are correct except for Q3 which had a typo. The question goes as below: Q3: If integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of an, what is the value of a? 1) a^n = 64 2) n = 6 Can you please give your answer and explanation?
from stat one
a^n=64
so possible value for 64=2^6 / 4^3 / 8^2
now an is multiple of 40320 so possible value for a^n anything out of 3(2^6 / 4^3 / 8^2) because 12,12,16 all r multiple of 40320
so 1 st not possible
from 2nd one
n=6
from 2 u cant say anything because 40320/6=6720
so value of A could be anyone of the factor of 6720
but if we take both to gather we will get 2^6 ans........
I think, Equilateral triangle can also be called as Isosceles triangle.
though all squares are recatangles, all rhombus are parallelogram and all congruent triangles are similar, i dont think equilateral triangle can be called as an isosceles triangle ...
Def of isosceles i presume is exactly 2 sides equal and not atleast 2 sides equal ...
I am not saying Isoscles triangle is equilateral triangle. What am saying is Equilateral triangle is an isosceles triangle with the third angle (first two angles are equal equal) equal to 60.
I believe that DS question if appears simple it means there is a catch similiar to the above question.We can not take isosceles with equilateral triangle here although equ.. triangle satisfies all properties of isc.
Thanks for the explanation. Your answers are correct except for Q3 which had a typo. The question goes as below: Q3: If integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of an, what is the value of a? 1) a^n = 64 2) n = 6 Can you please give your answer and explanation?
If just 1 is used, (a,n) can be (2,6) , (4,3), (8,2). So a can have any value out of 2,4 or 8. If statement 2 alone is used, a can have any values from 2, 3, 4, 5, 6, 7, 8. .. If both statement 1 and 2 are used, as value will be 2. So the answer is C.
Is MNP isosceles?(1)Exactly two of the angles, (2)
1 alone is sufficient to answer the question.
If two angles of the triangle are equal, the triangle has to be isosceles or equilateral (if all the angles are equal). Even if all the angles are equal, the triangle is equilateral and an equilateral triangle is isosceles.
2 alone cannot answer the question. if two angles of a triangle are not equal, the triangle still can be isosceles, if the other two angles are same. So we cannot answer for sure whether the triangle is isosceles or not.
I am not saying Isoscles triangle is equilateral triangle. What am saying is Equilateral triangle is an isosceles triangle with the third angle (first two angles are equal equal) equal to 60.
I can easily put this as a DS question.
I agree with you Ramviswa,
An equilateral triangle is an isosceles triangle with the third side equal to the other two.