The PaGaLGuY UnderDogs Team 2012

nits2811 · September 29, 2012, 4:41pm

@naarto said:
now that you guys had fun racking your brains over the seating arrangement, as an ex member, i take privilege of posting a question.
There are 16 people ready to hog. In how many ways can they be seated.

Arey kuch toh details do...kahan bithana h...kyu bithana h...kaise bithana h...baith ke kya karenge...kis cheez pe karen...kuch toh batao...

naarto · September 29, 2012, 4:43pm

@nits2811 said:

Arey kuch toh details do...kahan bithana h...kyu bithana h...kaise bithana h...baith ke kya karenge...kis cheez pe karen...kuch toh batao...

A better picture:

nits2811 · September 29, 2012, 5:16pm

@naarto said:
A better picture:

Arey sir kya google faik di...chain se nhi rehne doge kya..chalo dimag peet ta huun...thodi der mein deta huun answer...

michael88 · September 29, 2012, 5:16pm

@allan89 OA de do us passage ka with explanations....lagta hai koi aur nhi attempt karega itna phaad passage..!!

nits2811 · September 29, 2012, 5:19pm

@naarto said:
A better picture:

4 * 15!...galat mat bolna...baada soch samaj ke answer dia h..

naarto · September 29, 2012, 5:24pm

@nits2811 said:

4 * 15!...galat mat bolna...baada soch samaj ke answer dia h..

bingo! correct 😃 congratulations ;)

nits2811 · September 29, 2012, 5:25pm

@naarto said:

bingo! correct congratulations

hehe...yeh yeh..dhanyavaad

naarto · September 29, 2012, 5:27pm

@nits2811 said:

hehe...yeh yeh..dhanyavaad

bada soch samajhkar kiya na. aise hi karna ismei. ;).very dicey options can be given too :)

nits2811 · September 29, 2012, 5:40pm

@naarto said:

bada soch samajhkar kiya na. aise hi karna ismei. .very dicey options can be given too

yes i kno...aise questions are better done widout seeing the options...

abhi_14 · September 29, 2012, 8:51pm

@nits2811 said:

4 * 15!...galat mat bolna...baada soch samaj ke answer dia h..

Yr wat was ur explnation fr this one...as in acc to me: the frst person will have four places to select from and rest of the 15 people will b arrranged acc (i.e. the person will b treated as the ref pt fr other)..Is this correct??

abhi_14 · September 29, 2012, 8:57pm

@nits2811 said:

4 * 15!...galat mat bolna...baada soch samaj ke answer dia h..

Yr wat was ur explnation fr this one...as in acc to me: the frst person will have four places to select from and rest of the 15 people will b arrranged acc (i.e. the person will b treated as the ref pt fr other)..Is this correct??

amitshanky · September 30, 2012, 6:31am

Hello ,

Can anybody please mail CL mocks to me.

Do we have any google group then please add me there.

Thanks

amitshanky · September 30, 2012, 6:33am

@amitshanky said:
Hello ,

Can anybody please mail CL mocks to me.
Do we have any google group then please add me there.

Thanks

Thanks , I got it but please add me in google group. -:)

pratskool · September 30, 2012, 6:36am

ek accha Q dikha Quant thread se copy paste kar rha hai.... widout options...

What is the sum of all positive rationals p/30 (in lowest terms) which are less than 10?

nits2811 · September 30, 2012, 8:42am

@abhi_14 said:

Yr wat was ur explnation fr this one...as in acc to me: the frst person will have four places to select from and rest of the 15 people will b arrranged acc (i.e. the person will b treated as the ref pt fr other)..Is this correct??

yess kind off...what i did was...i placed A at one of the positions...then i rotated the diagram again and again to find out the number of symmetries it has...

nits2811 · September 30, 2012, 8:51am

@pratskool said:
ek accha Q dikha Quant thread se copy paste kar rha hai.... widout options...

What is the sum of all positive rationals p/30 (in lowest terms) which are less than 10?

My approach...as p shld b less than 300 and not divisible by 2 or 3 or 5...so now v are left with only odd nos...the sum ryte now is 22500...

Next subtract those nos divisible by 3 and not 2...

3, 9, 15...297

50*300/2=7500

Next subtract those nos divisble by 5 but not by 3 and 2...

5, 25, 35, 55, 65, 85,95....265,275,295

10*280/2 = 1400 + 10*320/2 = 1600

So 22500 - 7500-3000 = 12000

So the sum of values of p is 12k..

the sum of p/30 wld be 12000/30 = 400

allan89 · September 30, 2012, 9:03am

@pratskool said:
ek accha Q dikha Quant thread se copy paste kar rha hai.... widout options...

What is the sum of all positive rationals p/30 (in lowest terms) which are less than 10?

E (300) = 300 * 1/2 *2/3 *4/5 = 80

SUM OF all co primes = 300/2 *80 = 12000

sum of all rationals p/30 = 12000/30 =400

nits2811 · September 30, 2012, 9:05am

@allan89 said:

E (300) = 300 * 1/2 *2/3 *4/5 = 80

SUM OF all co primes = 300/2 *80 = 12000

sum of all rationals p/30 = 12000/30 =400

Oh damn..bhul gya tha aise bhi kar sakte h isse...need to start revising now...wld hv wasted roughly 2 extra mins...waarna ans 30 sec mein aa jaata iss method se...

allan89 · September 30, 2012, 9:25am

@nits2811 said:

Oh damn..bhul gya tha aise bhi kar sakte h isse...need to start revising now...wld hv wasted roughly 2 extra mins...waarna ans 30 sec mein aa jaata iss method se...

bina revise kiye hi 70 + phod to rahe ho ... aur kya zarurat ??

techsurge · September 30, 2012, 9:39am

@allan89 said:

E (300) = 300 * 1/2 *2/3 *4/5 = 80

SUM OF all co primes = 300/2 *80 = 12000

sum of all rationals p/30 = 12000/30 =400

allan bhai didnt get what exactly we are finding

are we finding sum of 1/30 +2/30...............................299/30 as all these fractions are less than 10

and of the form p/30

what exactly are finding

i got your method till finding no. of coprimes of 300 and then summing it but didnt get 12000/30 concept????

please explain